   Chapter 0.6, Problem 21E

Chapter
Section
Textbook Problem

Solve the equations in Exercises 1–26. 1 x − 9 x 3 = 0

To determine

To calculate: The solution of the equation 1x9x3=0.

Explanation

Given information:

The equation, 1x9x3=0.

Formula used:

Formula for difference of two squares,

(a+b)(ab)=a2b2

Where, a and b are real numbers.

Zero product property,

If ab=0 then either a=0 or b=0.

Condition to solve an equation of the form PQ=0,

If PQ=0, then P=0.

Calculation:

Consider the expression,

1x9x3=0

Make the denominator of both the term equal as below,

1x2xx29x3=0x29x3=0

As the above equation is in PQ=0 form

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find y and y. y=eex

Single Variable Calculus: Early Transcendentals, Volume I

4. For problems involving taxation in a competitive market, if supply is ?

Mathematical Applications for the Management, Life, and Social Sciences

Using for |x| < 1 and differentiation, find a power series for .

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 