   Chapter 0.6, Problem 25E

Chapter
Section
Textbook Problem

Solve the equations in Exercises 1–26. x + 4 x + 1 + x + 4 3 x = 0

To determine

To calculate: The solution of the equation x+4x+1+x+43x=0.

Explanation

Given information:

The equation, x+4x+1+x+43x=0.

Formula used:

The FOIL method,

Step1: Take product of first terms.

Step2: Take product of outer terms.

Step3: Take product of the inner terms.

Step4: Take product of the last terms.

Step5: Add all the terms.

The solution of the quadratic equation ax2+bx+c=0 is,

x=b±b24ac2a

Calculation:

Consider the expression,

x+4x+1+x+43x=0

Rewrite the above expression as,

x+4x+1=x+43x

Multiplying both side of the above equation by 3x(x+1),

x+4x+13x(x+1)=x+43x3x(x+1)3x(x+4)=(x+4)(x+1)3x2+12x=(x2+x+4x+4)3x2+12x+x2+x+4x+

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