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Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

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Chapter
Section
BuyFindarrow_forward

Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

In Exercises 1–4, complete the given tables.

Exponential Form
Logarithmic Form log 0.3 0.09 = 2 log 1 / 2 1 = 0 log 10 0.001 = 3 log 9 1 81 = 2 log 2 1 , 024 = 10 log 64 1 4 = 1 3

To determine

To fill: The following table,

Exponent Form
Logarithmic Form log0.30.09=2 log121=0 log100.001=3 log9181=2 log21,024=10 log6414=13
Explanation

Given information:

The given table is,

Exponent Form 101=10 55=3,125 63=216 0.53=0.125 414=2 34=181
Logarithmic Form

Consider the logarithmic, log0.30.09=2

Since the logarithmic form, logab=c means exponent form ac=b.

Then the logarithmic form log0.30.09=2 mean exponent form 0.32=0.09.

Consider the logarithmic, log121=0

Since the logarithmic form, logab=c means exponent form ac=b.

Then the logarithmic form log121=0 mean exponent form (12)0=1.

Consider the logarithmic, log100.001=3

Since the logarithmic form, logab=c means exponent form ac=b.

Then the logarithmic form log100.001=3 mean exponent form 103=0.001.

Consider the logarithmic, log9181=2

Since the logarithmic form, logab=c means exponent form ac=b.

Then the logarithmic form log9181=2 mean exponent form 92=181

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