Chapter 0.8, Problem 50E

### Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248

Chapter
Section

### Applied Calculus

7th Edition
Waner + 1 other
ISBN: 9781337291248
Textbook Problem

# In Exercises 47–56, solve the given equation for the indicated variable. 4 2 − 3 x = 256

To determine

To calculate: The value of x in equation, 4 23x =256.

Explanation

Given information:

The equation is, 4 23x =256

Formula used:

The logarithmic identity,

log a a=1

and log a b m =mlog a b

Here, a, m and b are real number.

Calculation:

Consider the equation,

4 23x =256

Take the log base 4 of both sides

log 4 256=log 4 4 23x

Now apply the logarithmic identity, log a b m =mlog a b

log

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