Chapter 0.9, Problem 1E

To determine

To find: The mean, median and mode for the given data.

Answer to Problem 1E

  $\text{Mean}=451.8,\text{Median}=399,\text{}\text{Mode}=\text{No}$

Explanation of Solution

Given information:

224, 272, 374, 478, 960, 394, 404, 308, 480, 624.

Calculation:

The given data is as follows:

224, 272, 374, 478, 960, 394, 404, 308, 480, 624.

The mean is the usual average, so we will add and then divide by the total number of observations to get:

  $\begin{array}{c}\frac{224+272+374+478+960+394+404+308+480+624}{10}=\frac{4518}{10}\\ =451.8\end{array}$

The median is the middle value, so first we will have to rewrite the list in numerical order:

224, 272, 308, 374, 394, 404, 478, 480, 624, 960.

We have ten integers, that means our median is $\frac{10+1}{2}=5.5$ or 5.5^th number in order, but it is not useful statement, so to calculate middle one in between 5^th and 6^th, we take their sum and divide it by two.

So, median would be $\begin{array}{c}\frac{394+404}{2}=\frac{798}{2}\\ =399\end{array}$

The mode is the number that is repeated more often than any other, so when we observe, we can conclude that there is NO mode.

Thus, $\text{Mean}=451.8,\text{Median}=399,\text{}\text{Mode}=\text{No}$