Kinetic energy K (Chapter 7) has dimensions kg · m 2 /s 2 . It can be written in terms of the momentum p (Chapter 9) and mass m as K = p 2 2 m (a) Determine the proper units for momentum using dimensional analysis. (b) The unit of force is the newton N, where 1 N = 1 kg · m/s 2 . What are the units of momentum p in terms of a newton and another fundamental SI unit?
Solution Summary: The author explains how to determine the proper unit of momentum using dimensional analysis.
Kinetic energy K (Chapter 7) has dimensions kg · m2/s2. It can be written in terms of the momentum p (Chapter 9) and mass m as
K
=
p
2
2
m
(a) Determine the proper units for momentum using dimensional analysis. (b) The unit of force is the newton N, where 1 N = 1 kg · m/s2. What are the units of momentum p in terms of a newton and another fundamental SI unit?
The quantity p = 3.14159c is a number with no dimensions, since it is a ratio of two lengths. Describe two or three other geometrical or physical quantities that are dimensionless.
The period (T) of a simple pendulum is given by the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Using dimensional analysis, determine the expression for the dimension of g in terms of the fundamental dimensions of mass (M), length (L), and time (T).
The followings are the measurements from one group of students:
M1=127.01 g, M2=49.40 g, Xi=33.90 cm, Xf=87.90 cm, Δt = 1.38 sec, what should be their μk value? Enter the result with correct significant figures.
Chapter 1 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
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