Chemistry: The Science in Context (Fifth Edition)
Chemistry: The Science in Context (Fifth Edition)
5th Edition
ISBN: 9780393614046
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Stacey Lowery Bretz, Geoffrey Davies
Publisher: W. W. Norton & Company
Question
Book Icon
Chapter 1, Problem 1.1VP

(a)

Interpretation Introduction

Interpretation: Two different images showing different arrangement of particles is given. The class of matter (an element, a compound, a homogenous mixture, or a heterogeneous mixture) and the physical state in the given images is to be stated.

Concept introduction: The space between the particles of solids is very less, so they just vibrate at their own place, while the specie between the particles of liquid is more as compared to solids. The space between particles of gas is very large so they can easily move and collide with each other and with the walls of the container.

When the atoms belonging to different elements are chemically combined in a fixed ratio then it leads to the formation of a compound while when the atoms of same type are combined together then it leads to the formation of an element.

The homogeneous mixture consists of same uniform composition and appearance throughout the mixture while the heterogeneous mixture has non-uniform composition throughout the mixture.

To determine: The class of matter (an element, a compound, a homogenous mixture, or a heterogeneous mixture) and the physical state in the given image.

(a)

Expert Solution
Check Mark

Answer to Problem 1.1VP

Solution

The given image shows that the species present inside the box is a pure compound and is present in the gaseous state.

Explanation of Solution

Explanation

The given image shows that the species present inside the box is a pure compound because it consists of only red and blue balls that are combined together. It consists of only two types of elements that are joined together; therefore it is not a homogeneous mixture. As it is seen that the space between the compounds is very large and they are free to move in the entire space, it means it represent the gaseous state.

(b)

Interpretation Introduction

To determine: The class of matter (an element, a compound, a homogenous mixture, or a heterogeneous mixture) and the physical state in the given image.

(b)

Expert Solution
Check Mark

Answer to Problem 1.1VP

Solution

The given image shows that the species present inside the box is a homogeneous mixture and is present in gaseous state.

Explanation of Solution

Explanation

The given image shows that the species present inside the box is a homogeneous mixture. It consists of two different balls that represent the elements. As two balls of a particular color are joined together, therefore, they form a molecule. As these two different molecules are uniformly distributed, therefore, the given mixture is homogeneous. As it is seen that there is a large space between the different molecules so that they are free to rotate. Therefore, the given molecules are in gaseous state.

Conclusion

The shape of matter depends on the arrangement of particles from which the matter is made up of that is whether it is solid, liquid or gas

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Chapter 1 Solutions

Chemistry: The Science in Context (Fifth Edition)

Ch. 1 - Prob. 1.2VPCh. 1 - Prob. 1.3VPCh. 1 - Prob. 1.4VPCh. 1 - Prob. 1.5VPCh. 1 - Prob. 1.6VPCh. 1 - Prob. 1.7VPCh. 1 - Prob. 1.8VPCh. 1 - Prob. 1.9QPCh. 1 - Prob. 1.10QPCh. 1 - Prob. 1.11QPCh. 1 - Prob. 1.12QPCh. 1 - Prob. 1.13QPCh. 1 - Prob. 1.14QPCh. 1 - Prob. 1.15QPCh. 1 - Prob. 1.16QPCh. 1 - Prob. 1.17QPCh. 1 - Prob. 1.18QPCh. 1 - Prob. 1.19QPCh. 1 - Prob. 1.20QPCh. 1 - Prob. 1.21QPCh. 1 - Prob. 1.22QPCh. 1 - Prob. 1.23QPCh. 1 - Prob. 1.24QPCh. 1 - Prob. 1.25QPCh. 1 - Prob. 1.26QPCh. 1 - Prob. 1.27QPCh. 1 - Prob. 1.28QPCh. 1 - Prob. 1.29QPCh. 1 - Prob. 1.30QPCh. 1 - Prob. 1.31QPCh. 1 - Prob. 1.32QPCh. 1 - Prob. 1.33QPCh. 1 - Prob. 1.34QPCh. 1 - Prob. 1.35QPCh. 1 - Prob. 1.36QPCh. 1 - Prob. 1.37QPCh. 1 - Prob. 1.38QPCh. 1 - Prob. 1.39QPCh. 1 - Prob. 1.40QPCh. 1 - Prob. 1.41QPCh. 1 - Prob. 1.42QPCh. 1 - Prob. 1.43QPCh. 1 - Prob. 1.44QPCh. 1 - Prob. 1.45QPCh. 1 - Prob. 1.46QPCh. 1 - Prob. 1.47QPCh. 1 - Prob. 1.48QPCh. 1 - Prob. 1.49QPCh. 1 - Prob. 1.50QPCh. 1 - Prob. 1.51QPCh. 1 - Prob. 1.52QPCh. 1 - Prob. 1.53QPCh. 1 - Prob. 1.54QPCh. 1 - Prob. 1.55QPCh. 1 - Prob. 1.56QPCh. 1 - Prob. 1.57QPCh. 1 - Prob. 1.58QPCh. 1 - Prob. 1.59QPCh. 1 - Prob. 1.60QPCh. 1 - Prob. 1.61QPCh. 1 - Prob. 1.62QPCh. 1 - Prob. 1.63QPCh. 1 - Prob. 1.64QPCh. 1 - Prob. 1.65QPCh. 1 - Prob. 1.66QPCh. 1 - Prob. 1.67QPCh. 1 - Prob. 1.68QPCh. 1 - Prob. 1.69QPCh. 1 - Prob. 1.70QPCh. 1 - Prob. 1.71QPCh. 1 - Prob. 1.72QPCh. 1 - Prob. 1.73QPCh. 1 - Prob. 1.74QPCh. 1 - Prob. 1.75QPCh. 1 - Prob. 1.76QPCh. 1 - Prob. 1.77QPCh. 1 - Prob. 1.78QPCh. 1 - Prob. 1.79QPCh. 1 - Prob. 1.80QPCh. 1 - Prob. 1.81QPCh. 1 - Prob. 1.82QPCh. 1 - Prob. 1.83QPCh. 1 - Prob. 1.84QPCh. 1 - Prob. 1.85QPCh. 1 - Prob. 1.86QPCh. 1 - Prob. 1.87QPCh. 1 - Prob. 1.88QPCh. 1 - Prob. 1.89APCh. 1 - Prob. 1.90APCh. 1 - Prob. 1.91APCh. 1 - Prob. 1.92APCh. 1 - Prob. 1.93APCh. 1 - Prob. 1.94APCh. 1 - Prob. 1.95APCh. 1 - Prob. 1.96APCh. 1 - Prob. 1.97APCh. 1 - Prob. 1.98AP
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