2. A system that uses a two-level page table has 212-byte pages and 32 -bit virtual addresses. The first 8 bits of the address serve as the index into the first-level page table. (a) (b) How many bits specify the second-level index? table? How many entries are in a level-one page How many entries are in a level-two page table? How many pages are in the virtual address space? (b)
Q: What exactly is a virtual address, and how does one go about converting one into a real one?
A: The virtual address is a logical address created by the CPU that does not exist in the real world.…
Q: Suppose you have a byte-addressable virtual address memory system with eight virtual pages of 64…
A: Answer: 1. Since it is be addressable, each page consists of 8 bits(i.e 1byte).It consists…
Q: For a machine with 4 GB virtual memory, 1 GB physical memory, 8 KB page size, 64 KB direct-mapping…
A:
Q: Consider a system with 39-bit virtual addresses, 44-bit physical addresses, 4096 byte pages, and the…
A: Physical Address: It is a memory address or location of memory cell in the main memory. Pages: Page…
Q: Consider a logical address space of 64 pages with 2048 words per page; mapped onto a physical memory…
A: A virtual address is known as logical address, it provide reference for CPU to access the physical…
Q: Give the number of the virtual page that the byte with virtual memory address 52000 belongs to,…
A: Page size = 8KiB This means page offset = log 8KiB = 13 bits So the least significant 13 bits will…
Q: . Suppose we have 2 bytes of virtual memory and 28 bytes of physical main memory. Suppose the page…
A: Given: Virtual memory size=210 Physical memory size=28 Size of the page=24.
Q: Consider a system with 256Mbytes of main memory with page size of 4Kbytes. It has a logical address…
A: Answer: Given Main Memory 256Mbytes Page Size =4Kbytes and logical address=26 bits
Q: 1. Consider a 32bit address space with 2K bytes page size, assuming that each entry consists of 4…
A: Solution : Address Space consist of 32 bits, program size is 2^32 bytes i.e. 4GB. Page Size = 2K…
Q: How many bits are in a physical address?
A: There are 4 pages frames of size 64 each, or 22 x 26=28. So each physical address has 8 bits.
Q: A machine has 48-bit virtual addresses and 32-bit physical addresses. Pages are 8 KB. How many…
A: Actually, given information: A machine has 48-bit virtual addresses 32-bit physical addresses.
Q: Suppose we have a computer system with 44-bit logical addresses, page size of 64KiB, and 4 bytes per…
A: The answer is explained in detailed below:
Q: a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and a…
A: Given : Physical memory = 224 bytes Logical address space = 256 pages Page size = 210 bytes
Q: a) A paging system with 512 pages of logical address space, a page size of 2³ and number of frames…
A: Here in this question we have given Page size = 256 No of frame = 1024 Page in logical address=…
Q: puter system with a 16-bit logical address and 2-KB page size. The system supports up to 1MB of…
A: Consider a computer system with a 16-bit logical address and 2-KB page size. The system supports up…
Q: 5. Your system has an 8-way set associative cache and addresses and data of length 16 bits. The…
A: Since it is given that set index bits are 9, we have Total sets = 29 = 512
Q: Compare between the status and control flags? Explain the status flags for the operation AEH+37H ?…
A: Status Flags – There are 6 flag registers in 8086 microprocessor which become set(1) or reset(0)…
Q: 5a Into what line would bytes with each of the following addresses be stored 0001 0001 0001 1011…
A:
Q: Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. (a) What is the…
A: Given Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is…
Q: A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses…
A: Given that: Main memory size = 64K = 26 X 210 = 216 words Cache memory size = 1K = 20 X…
Q: 5. Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. a) What is the…
A: A virtual address space or address space is the set of ranges of virtual addresses that an operating…
Q: Computer Science Explain in detail the steps in translating a 24-bit Virtual Address to a 32-bit…
A: The answer is
Q: Consider a system with 256Mbytes of main memory with page ize of 4Kbytes. It has a logical address…
A: Here in this question we have given main memory size= 256MB. Page size = 4KB Logical address space=…
Q: 2. Consider the following assumptions: Size of virtual address: 32 bits Size of physical memory: 2…
A: Size of the Page table = Number of pages * Page table entry.
Q: A computer has 32-bit virtual addresses and the page size is 2^9 KB. Suppose the text, data, and…
A: Here the virtual address size is 32 bits. Page size is 29 Bytes. Two level page table.
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: To find the solution for given question: How many blocks of main memory are there? What is the…
Q: Assume 32 bit memory addresses , which are byte addresses. You have direct mapped cache with…
A: Block size = 8 bytes So block offset bits = 3 bits Total # of cache blocks = 128 So index bits = 7…
Q: Computer Science Please explain in detail the steps in translating a 24 bit virtual address to a 32…
A:
Q: Assume you have a small virtual address space of size 2048 KB, and that the system uses paging, but…
A: Below is the answer to the above question. I hope this will meet your requirement.
Q: Q: A digital computer has a memory unit of 64k * 16 and a cache memory of 1k words. The cache uses…
A: i) Answer: Tag = 6 bitsIndex = 10 bitsBlock = 8 bitsWord = 2 bits Explanation: Given that:…
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: Please find the answer to the above question below:
Q: 1. Write about the entire details of memory structure design and characteristics. 2. How much the…
A: answer is given below:-
Q: For the following problems assume 1 kilobyte (KB) 1024 kilobytes. 1024 bytes and 1 megabyte (MB) For…
A: a) Bits in offset = log2(page size)Given, every byte in the page have a unique address so we have…
Q: Consider a system with 36-bit addresses that employs both segmentation and paging. Assume each PTE…
A: This is Operating system related question.
Q: If a system has a 4-MB address space, where each page is 4 KB, and page table accesses take 100 nS,…
A: Given Data : Size of Address Space = 4 MB Size of the page = 4 KB One page tablet/page access…
Q: Consider a system that has a 20-bit virtual address, a 16-bit physical address, and a 4-KB page…
A:
Q: Our system is using virtual memory and has 48-bit virtual address space and 32-bit physical address…
A: A. Page size = 8KiB So page offset bits = 13 bits Total # of page table entries required = total…
Q: 4. Assume 32 bit memory addresses, which are byte addresses. You have a direct-mapped cache with a…
A: Block size = 8 bytes So block offset bits = 3 pieces All out # of cache blocks = 128 So index…
Q: Consider a system with 256Mbytes of main memory with page size of 4Kbytes. It has a logical address…
A: Below is the answer to above questions.
Q: . suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and…
A: Actually, cache is a fast access memory. Which located in between cpu and secondary memory.
Q: Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE…
A: Data given in the question, 32-bit address system page size of 2 KB PTE (Page Table Entry) size of 1…
Q: Question 1 A memory cache using a 41-bits address with 9 bits for index and 10 bits for offset. How…
A: Answer: This question based on memory management so we have answered question in next steps.
Q: a) How many bits are in a virtual address? b) How many bits are in a physical address? c) What…
A:
Q: Ql(a). Consider a logical address space of 64 pages with 1-KB frame size mapped onto a physical…
A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: 2) What are the purposes of both segmentation and physical address generation? Explain with draw and…
A: Lets understand what is required from the given question. We need to define purpose of segmentation…
Q: QUESTION 2 Suppose a computer using direct mapped cache is using 216 (64K) bytes of byte-addressable…
A: Here, we are given a direct mapped cache and main memory size with cache size and cache block size.…
Q: Suppose, a primary memory size is 56 bytes and frame size is 4 bytes. For a process with 20 logical…
A: Page size = Frame size = 4 bytes. So page offset bits = 2 bits. The least significant 2 bits will…
Q: A system that uses a two-level page table has 212 bytes pages and 32-bit virtual addresses. Assume…
A: Data given, 2^12 bytes pages 32-bit virtual addresses 4-byte each entry 10 bits of address serve as…
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- Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is the main advantage of a multilevel page table over a single-level one?(b) With a two-level page table, 16-KB pages, and 4-byte entries, how many bits should be allocated for the top-level page table field and how many for the next-level page table field? Explain.6) In a 64 bit machine with a 8 KB page size for virtual memory, how many entries are there in a single level page table? What is the size of each entry in the page table in bits?Suppose that a machine has 42-bit virtual addresses and 32-bit physical addresses.{a} How much RAM can the machine support (each byte of RAM must be addressable)?{b} What is the largest virtual address space that can be supported for a process?{c} If pages are 2 KB, how many entries must be in a single-level page table?{d} If pages are 2 KB and we have a two-level page table where the first level is indexed by 15-bits, then how many entries does the first-level page table have?{e} With the same setup as part {d}, how many entries are in each second-level page table?{f} What is the advantage of using a two-level page table over single-level page table?
- 1.What is the difference between bit address 7CH and byte address7CH? What is the specific location of bit address 7CH in memory?On a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and a page size of 210 bytes, 1. How many bits are needed to form the logical address? 2. What is the frame size (in bytes)? 3. How many bits comprising the number of frames?Suppose a computer using direct mapped cache has 4G Bytes of main memory and a cache of 256 Blocks, where each cache Block has 16 Words, and Word Size is 4 Bytes. a)How many blocks of main memory? b)What is the format of a memory address as seen by the cache (Tag, Block and Word fields)? c)To which cache block will the memory reference 0000146A in Hex?
- Suppose a computer using direct mapped cache has 2^24 bytes of byte- addressable main memory and a cache size of 64K bytes, and each cache block contains 32 bytes. (Note: 64K = 26 * 210) a) How many blocks of main memory are there? b) What is the format of a memory address as seen by cache, i.e., what are the sizes of the tag, block, and offset fields?On a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and a page size of 210 bytes. 1. How many bits are needed to store an entry in the page table (how wide is the page table)? Assume a valid/invalid 1-bit is included in each entry. 2. If the page table is stored in the main memory with 250nsec access time, how long does a paged memory reference take? 3. If the page table is implemented using associative registers that takes 95nsec. and main memory that takes 200nsec, what is the total access time if 75% of all memory references find their entries in the associative registers?Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB. Answer the following questions, assuming a virtual address 0x00030f40 A. What is the virtual page number (VPN) and the offset in binary for the given virtual address? B. How many virtual pages are there in the system?
- Suppose a computer using fully associative cache has 4 Gbytes of byte-addressable main memory and a cache of 256 blocks, where each cache block contains 32 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address? Provide the names and the sizes of the fields. c) To which cache block will the memory address 0x01752 map?Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE (Page Table Entry) size of 1 B. Answer the following questions, assuming a virtual address 0x00030f40 a. What is the virtual page number (VPN) and the offset in binary for the given virtual address? b. How many virtual pages are there in the system?A system with page size = 8, and memory space of 128, and a process with a request of 29 How many bits for offset? How many bits for page#? How many bits for logical address? How many bits for physical address? How many bits for the frame? A system with page size = 8, and memory space of 128, and a process with a request of 29 How many bits for offset? How many bits for page#? How many bits for logical address? How many bits for physical address? How many bits for the frame?