# To graph: The equation 2 x − y + 1 = 0 and check the equation for symmetry.

BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1, Problem 112RE
To determine

Expert Solution

## Answer to Problem 112RE

The equation 2xy+1=0 is not symmetric and the graph is as follows:

### Explanation of Solution

Given information:

The equation of line 2xy+1=0

Formula used:

The equation is said to have symmetry about the x -axis when the equation remains unchanged on replacing y by y

Graphically it can be said that the graph remains unchanged when reflected in the x -axis.

The equation is said to have symmetry about the y -axis when the equation remains unchanged on replacing x by x

Graphically it can be said that the graph remains unchanged when reflected in the y -axis.

The equation is said to have symmetry about the origin if it is symmetric about x -axis and y -axis that is the equation remains unchanged on replacing x by x or y by y

Graphically it can be said that the graph remains unchanged when rotated with an angle of 180 about the origin.

Calculation:

It is provided that the equation of line is 2xy+1=0 (1)

Firstly replace y by y in (1)

2x(y)+1=02x+y+1=0

The equation obtained is not the same as the original one.

Hence, 2xy+1=0 is not symmetric about x -axis

Next, replace x by x in (1)

2(x)y+1=02xy+1=02x+y1=0

The equation obtained is not the same as the original one.

Hence, 2xy+1=0 is not symmetric about y -axis.

Thus, 2xy+1=0 is not symmetric about origin.

For plotting:

 x 2x−y+1=0 (x.y) 012 135 (0,1)(1,3)(2,5)

We plot these points to get the graph as follows:

Thus, 2xy+1=0 is neither symmetric about x -axis nor about y -axis.

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