A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions. Concept Introduction: Kinetic energy (E k ) is defined as, half of the mass (m) times square of velocity ( υ ) of a object. K E = 1 / 2 m v 2 Here, m is mass of air, and v is velocity of air.

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Answer 1

Question

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

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Answer 2

Question

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

Expert Solution & Answer

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Answer 3

Question

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

Expert Solution & Answer

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Answer 4

Question

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

Expert Solution & Answer

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Answer 5

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

Answer 6

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

Answer 7

Chapter 1, Problem 1.23P

Interpretation Introduction

Interpretation:

A wind turbine with a rotor diameter of 77 m produces 1.5 MW of electrical power at a wind speed of 12 m.s-1. The fraction of the kinetic energy of the air passing through the turbine is converted to electrical power needs to be calculated. The density is assumed as 1.25 kg.m-3 for air at the operating conditions.

Concept Introduction:

Kinetic energy (E_k) is defined as, half of the mass (m) times square of velocity ( υ ) of a object.

KE= 1/2mv2

Here, m is mass of air, and v is velocity of air.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 1 - Prob. 1.1P Ch. 1 - Prob. 1.2P Ch. 1 - Prob. 1.3P Ch. 1 - Prob. 1.4P Ch. 1 - Prob. 1.5P Ch. 1 - Prob. 1.6P Ch. 1 - Prob. 1.7P Ch. 1 - Prob. 1.8P Ch. 1 - Prob. 1.9P Ch. 1 - Prob. 1.10P

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Chapter 1 Solutions