Suppose that the cost of electrical energy is $0.12 per kilowatt hour and that your electrical bill for 30 days is $60. Assume that the power delivered is constant over the entire 30 days. What is the power in watts? If this power is supplied by a voltage of 120 V, what current flows? Part of your electrical load is a 60 W light that is on continuously. By what percentage can your energy consumption be reduced by turning this light off?
Suppose that the cost of electrical energy is $0.12 per kilowatt hour and that your electrical bill for 30 days is $60. Assume that the power delivered is constant over the entire 30 days. What is the power in watts? If this power is supplied by a voltage of 120 V, what current flows? Part of your electrical load is a 60 W light that is on continuously. By what percentage can your energy consumption be reduced by turning this light off?
1.) An incandescent lamp, rated at 100 watts, gives a certain amount of light when placed across the 120V ac power line. Would the amount of light increase, decrease or remain the same, when the lamp is placed across a 120V dc power line? Discuss.
2.) Explain what is meant by effective current and effective voltage.
A no. 000 AWG wire is 100 meters long. For no. 000 wire, it has a wire resistance of 0.0618 ohms per 1000ft. Determine the power loss if the current flowing through the wire is 18 amperes.How much must you pay for the loss in the previous problem due to the voltage drop if during the whole month, you used the wire for 300 cumulative hours? Assume a rate of 5 pesos per kWh. Can you solve for it? If yes, solve the value in php. If not, type (unsolvable).
Heat energy is often measured in calories and 1 calorie = 4.184 Joule. It is desired to design a heating element to boil a certain amount of water in 2 min requiring 40-kcal heat energy. If the heater is to operate at 110-V, calculate its current and power ratings.
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What is an electric furnace and how does it work?; Author: Fire & Ice Heating and Air Conditioning Inc;https://www.youtube.com/watch?v=wjAWecPGi0M;License: Standard Youtube License