Electric machinery fundamentals
5th Edition
ISBN: 9780073529547
Author: Chapman, Stephen J.
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 1, Problem 1.2P
A flywheel with a moment of inertia of
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Chapter 1 Solutions
Electric machinery fundamentals
Ch. 1 - What is torque? What role does torque play in the...Ch. 1 - What is Amperes law?Ch. 1 - What is magnetizing intensity? What is magnetic...Ch. 1 - How does the magnetic circuit concept aid in the...Ch. 1 - What is reluctance?Ch. 1 - What is a ferromagnetic material? Why is the...Ch. 1 - How does the relative permeability of a...Ch. 1 - Prob. 1.8QCh. 1 - What are eddy current losses? What can be done to...Ch. 1 - Why are all cores exposed to ac flux variations...
Ch. 1 - What is Faraday law?Ch. 1 - What conditions are necessary for a magnetic field...Ch. 1 - What conditions are necessary for a magnetic field...Ch. 1 - Prob. 1.14QCh. 1 - The linear machine in Figure 1-19 is running at...Ch. 1 - Just how does a decrease in flux produce an...Ch. 1 - Will current be leading or lagging voltage in an...Ch. 1 - What are real, reactive, and apparent power? What...Ch. 1 - What is power factor?Ch. 1 - Prob. 1.1PCh. 1 - A flywheel with a moment of inertia of 4kgm2 is...Ch. 1 - A force of 10 N is applied to a cylinder of radius...Ch. 1 - A motor is supplying 50Nm of torque to its load....Ch. 1 - A ferromagnetic core is shown in Figure P1-2. The...Ch. 1 - A ferromagnetic core with a relative permeability...Ch. 1 - A two-legged core is shown in Figure P1-4. The...Ch. 1 - A core with three legs is shown in Figure P1-5....Ch. 1 - A two-legged core is shown in Figure P1-4. The...Ch. 1 - A wire is shown in Figure P1-7 that is moving in...Ch. 1 - Repeat Problem 1-10 for the wire in Figure P1-8.Ch. 1 - Prob. 1.12PCh. 1 - A core with three legs is shown in Figure P1-10....Ch. 1 - A two-legged magnetic core with an air gap is...Ch. 1 - A transformer core with an effective mean path...Ch. 1 - The core shown in Figure P1-2 has the flux shown...Ch. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Demonstrate that Equation (1-59) can be derived...Ch. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - For the linear machine of Problem 1-22: When this...
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- 5. Calculate the force exerted by each conductor, 9 in. long, on the armature of a DC motor, when it carries a current of 100 amp and lies in a field density of which is 55,000 lines per square inch.arrow_forwardA square loop of wire is oriented in a 12-tesla magnetic field directed to the left as shown. The loop has a side length of 30 cm. At time t = 0, the loop is connected to a battery that results in 4 amps of current traveling counter-clockwise through the loop. Determine the magnitude and direction of the net torque acting on the loop the instant after the battery is connected. For the direction, imagine that you are looking at the loop from above.arrow_forwardThe following data are given for a wind turbine: Blade length, l = 45 m Wind speed, U = 12 m/sec Air density, r = 1.25 kg/m3 Find the following: a) Total wind power in MW that can be extracted b) Maximum wind turbine power in MW that can be generated c) Actual wind turbine power in MW if the power coefficient is 0.38 d) Blade tip speed in m/s if the rotational speed is 7 rpm e) Tip speed ratioarrow_forward
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- A 4-pole, lap-wound dc machine has 738 armature conductors. Its field winding is excited from a dc source to create an air-gap flux of 27 mWb/pole. The machine (generator) is run from a primemover (diesel engine) at 1200 rpm. It supplies a current of 80 A to an electric load. (a) Calculate the electromagnetic power developed. (b) What is the mechanical power that is fed from the primemover to the generator?arrow_forward2. A 4 pole, 60 Hz, 11kV turbo alternator has a rating of 230 MW, power factor of 0.76 lagging. The rotor has moment of inertia of 23000 kg-m2. Calculate (i) Energy stored in the rotor (ii) Inertia constant H and (iii) Angular momentum in mechanical radians and electrical radians and electrical degrees and per unit radian and degrees Note that : moment of inertia J=23000arrow_forwardThe mechanical part in the figure with the conversion ratio n = N1 / N2 = 1/2 is known that the second-side torque T2 = 10 Nm. In which option the rotation angle of the first side (Ɵ1 (t)) is shown correctly. (J1 = 0.1, J2 = 0.4, B1 = 0.005, B2 = 0.02)arrow_forward
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