# 1.38 Express (a) 275 o C in K, (b) 25.55 K in o C, (c) -47.0 o C in o F, and (d) 100 o F in K.

### Chemistry for Engineering Students

4th Edition
Lawrence S. Brown + 1 other
Publisher: Cengage Learning
ISBN: 9781337398909

Chapter
Section

### Chemistry for Engineering Students

4th Edition
Lawrence S. Brown + 1 other
Publisher: Cengage Learning
ISBN: 9781337398909
Chapter 1, Problem 1.38PAE
Textbook Problem
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## 1.38 Express (a) 275 oC in K, (b) 25.55 K in oC, (c) -47.0 oC in oF, and (d) 100 oF in K.

(a)

Interpretation Introduction

To convert:

The 275° C temperature in K.

### Explanation of Solution

The equation to relate both temperatures is as follows:T(K)=T°(C)+273.15T(K)=

(b)

Interpretation Introduction

To convert: The 25.55K temperature in oC.

(c)

Interpretation Introduction

To convert: The -47.0º C temperature in oF.

(d)

Interpretation Introduction

To convert: The 100.0º F temperature in K.

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