   Chapter 1, Problem 13P ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# Solve the inequality ln(x2 – 2x − 2) ≤ 0.

To determine

To solve: The inequality ln(x22x2)0.

Explanation

Given:

The inequality: ln(x22x2)0.

Calculation:

Consider the inequality ln(x22x2)0.

The inequality is not possible as ln(x22x2) value is always positive.

That is, ln(x22x2)>0.

Obtain the root of (x22x2)

x=2±4+82=2±4(3)2=1±3

Thus the intervals are follows,

x(,13)(1+3

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Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 