Steel Design (Activate Learning wi...

6th Edition
Segui + 1 other
ISBN: 9781337094740



Steel Design (Activate Learning wi...

6th Edition
Segui + 1 other
ISBN: 9781337094740
Textbook Problem

A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. Δ L . A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P / Δ L = 1392 kips/in. What is the modulus of elasticity?

To determine

The modulus of elasticity of the metal specimen.



The diameter of metal specimen is 12inch.

The gage length is 4inches.

The slope of straight line is 1392kips/in.

Concept Used:

Write the expression for deformation.


Rearrange the equation to calculate the young’s modulus.

E=PLA×ΔL      ...... (I)

Here, the modulus of elasticity is E, the slope of straight line from load-displacement graph is PΔL, the gage length is L and the cross-sectional area is A.


Calculate the cross-sectional area of metal specimen.

A=π4×d2      ...... (II)

Here, diameter of the metal specimen is d.

Substitute 12inch for d in Equation (II).


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