Chapter 1, Problem 1.6P

Interpretation Introduction

Interpretation:

The molar mass of given compound has to be calculated.

Concept Introduction:

Ideal gas law:

The relationship between pressure, temperature and volume of a gas given by ideal gas law,

  $\begin{array}{l}\text{PV}\text{=}\text{nRT}\\ \text{Where,}\\ P\text{-}p\text{ressure}\\ {\text{T}}_{}\text{-temperature}\\ {\text{V}}_{}\text{-volume}\\ \text{n-number of mole}\end{array}$

$\text{n-number of mole}\text{=}\frac{mass}{molarmass}$

Substitute the above equation in ideal gas equation,

  $\begin{array}{l}\text{P}\text{=}\frac{\text{Mass}\times \text{R}\times \text{T}}{Molarmass\times \text{V}}\\ Density(d)=\frac{Mass}{Volume}\\ P\text{=}\frac{d\times \text{RT}}{Molarmass}\\ Molarmass=\frac{dRT}{P}\end{array}$