Chemistry - With Access (Looseleaf) (Custom)
Chemistry - With Access (Looseleaf) (Custom)
3rd Edition
ISBN: 9781259896491
Author: Burdge
Publisher: MCG
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Textbook Question
Chapter 1, Problem 1KSP

Given that the density of gold is 19 .3 g/cm 3 , calculate the volume ( in cm 3 ) of a gold nugget with a mass of 5.98 g.

( a ) 3 .23 cm 3 ( b ) 5 .98 cm 3 ( c ) 115 cm 3 ( d ) 0 .310 cm 3 ( e ) 13 .3 cm 3

Expert Solution & Answer
Check Mark
Interpretation Introduction

Interpretation:

The volume (in cm3) of the gold nugget with given massis to be determined.

Concept Introduction:

The relationship between density, volume, and mass is as:

d=mV …… (1)

Here, d is the density, V is the volume,and m is the mass of the given sample.

Density is defined as the ratio of mass of the sample to its volume. It is generally expressed in gcm3.

Answer to Problem 1KSP

Correct answer:

The volume of the given gold nugget is 0.310cm3. Thus, option (d) is correct.

Explanation of Solution

Reason for correct option:

Use equation (1) to calculate the density of the gold nugget as follows:

d=mV

Now, rearrange equation (1) so that the volume of the gold nugget is calculated as:

V=md

Substitute, 19.3 gcm3 for density (d) and 5.98 g for mass (m) in the above equation as:

V=5.98 g19.3 gcm3=0.30984 cm30.310 cm3

Hence, option (d) is correct.

Reasons for incorrect options:

Option (a) is incorrect because according to the above calculation, the value 3.23 cm3 cannot be obtained. So, it is a wrong answer.

Option (b) is incorrect because according to the above calculation, the value 5.98 cm3 cannot be obtained. So, it is a wrong answer.

Option (c) is incorrect because according to the above calculation, the value 115 cm3 cannot be obtained. So, it is a wrong answer.

Option (e) is incorrect because according to the above calculation, the value 13.3 cm3 cannot be obtained. So, it is a wrong answer.

Hence, options ( a), (b), (c), and (e) are incorrect.

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Chapter 1 Solutions

Chemistry - With Access (Looseleaf) (Custom)

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