Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 1, Problem 20Q
To determine
The angular size of the Venus as seen from the earth on April 18, 2006.
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The Earth is about 12800 (1.28 x 104) km in diameter. If you drew the Earth to scale on your model (model is attatched here) how many centimeters across would the dot measure? Show your work here:
Scaled diameter of Earth on model = _____________ cm. Based on this calculation, is your model’s scale a good one for showing the relative sizes of the planets?
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Next you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law.
Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU
Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU
(2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5)
Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU.
A) Calculate a in AU.
B) Convert your measurement of the moon's orbital period from days to years.
C) By Newton's form of Kepler's third law, calculate the mass of the planet.
D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.
On August 27, 2003, the planet Mars was at a distance of 0.373 AU from Earth. The diameter of Mars is 6788 km. Calculate the angular diameter of Mars, as seen from Earth on August 27, 2003. Give your answer in arcminutes.
Chapter 1 Solutions
Universe: Stars And Galaxies
Ch. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7QCh. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10Q
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- Draw a picture that explains why Venus goes through phases the way the Moon does, according to the heliocentric cosmology. Does Jupiter also go through phases as seen from Earth? Why?arrow_forwardNeptune is an average distance of 4.5×10^9 km from the Sun. - How many astronomical units (AU) is Neptune from the Sun? One AU is 1.50×10^8 km. - Estimate the length of the Neptunian year using your answer from part (a).arrow_forwardLet's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Mercury. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth yearsarrow_forward
- Let's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Answer for the highlighted planet in each question. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Earth. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth yearsarrow_forwardGive me the right answer please and thank you, take your timeCalculate the amount of time it takes for light reflected off the surface of a distant planet to reach us.1. Sunlight takes about 8.3 minutes to travel from the Sun to Earth. What is the Sun-Earth distance in AU? (Give your answer rounded to the nearest AU).2.Light is reflected off the surface of a planet 5.2 AU away from us. How long does it take this light to reach us from the planet? Give your answer in minutes, rounded to exactly one decimal place.arrow_forwardFrom the data measured read off the period, P and the orbital radius, a from thegraph for the moon Ganymede . These values will have units of hours for the period P, and Jupiter Diameters (J.D.) for a. Enter your results here:P (period) = _________ hours a (orbital radius) = ________ J.D. After,In order to use Kepler's Third Law, you need to convert the period into years, using: 1 day = 24 hours and 1 year = 365.25 days. The orbital radius must be converted to A.U., using 1050 J.D. = 1 A.U. Enter your converted values here: P (period) = _________ years a (orbital radius) = ________ A.U.arrow_forward
- Why Venus’ phase observation made it very difficult to argue against the heliocentric model.arrow_forwardAn object takes 68 years to orbit the Sun. What is its average distance (in AU) from the Sun? Saturn has an orbital period of 29.5 years and Neptune has an orbital period of 165 years. How many orbits does Saturn make for each Neptune orbit? If a planet has an average distance from the Sun of 8.5 AU, what is its orbital period?arrow_forwardWhich planet should I start with? USE IMAGE AS REFERNCEarrow_forward
- Use the small-angle formula to calculate the angular diameter (in arc minutes) of Mars (d = 6.79 ✕ 103 km) as seen from Earth if Mars were at the location of the Sun (D = 1.5 ✕ 108 km).arrow_forwardVenus has an average distance to the sun of 0.723 AU. How do you calculate the orbital period of venus, and then calculate itarrow_forward- How far (in km) is 3.5 lightyears(ly) – the distance traveled by light in one Earth year? - How much is this same value in parsecs and (C) in astronomical units (AU)? Use 299,732 km/s for the speed of light (c) and 1 year = 365 days. Show your solution and write your answer in both regular notation and scientific notation.arrow_forward
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