Chapter 1, Problem 36GP

(a)

To determine

Total seconds in 1.00 year.

Answer to Problem 36GP

The number of seconds in 1 year is $3.15\times {10}^7\sec$

Explanation of Solution

Given:

Time is 1 year.

Formula used:

1 year = 365 days

Calculation:

Since 1 year = 365 days

So,

  $\begin{array}{l}1\text{ year }=365\text{ days}\\ 1\text{ year }=365\times 24\times 60\times 60\sec \\ 1\text{year}=\text{31536000 }\sec \\ 1\text{year}=3.15\times {10}^7\sec \end{array}$

Conclusion:

Thus, the number of seconds in 1 year is $3.15\times {10}^7$

(b)

To determine

Total nanoseconds in 1.00 year

Answer to Problem 36GP

The number of nanoseconds in 1 year is $3.15\times {10}^{16}\text{ns}$

Explanation of Solution

Given:

Time is 1 year.

Formula used:

1 year = 365 days

  $1\text{ns}={10}^{-9}\sec$

Calculation:

Since 1 year = 365 days

So,

  $\begin{array}{l}1\text{ year }=365\text{ days}\\ 1\text{ year }=365\times 24\times 60\times 60\\ 1\text{year}=\text{31536000}\sec \\ 1\text{year}=3.15\times {10}^7\sec \\ 1\text{year}=3.15\times {10}^{16}\text{ns}\end{array}$

Conclusion:

Thus, the number of nanoseconds in 1 year is $3.15\times {10}^{16}\text{ns}$

(c)

To determine

Total number of years in 1.00 second.

Answer to Problem 36GP

The number of years in 1 second is $3.17\times {10}^{-8}\text{years}$

Explanation of Solution

Given:

Time is 1 second.

Formula used:

1 year = 365 days

Calculation:

Since 1 year = 365 days

  $\begin{array}{c}1\text{ year }=365\text{ days}\\ 1\text{ year}=365\times 24\times 60\times 60\\ 1\text{year}=\text{31536000}\sec \\ 1\text{year}=3.15\times {10}^7\sec \\ 1\sec =\frac{1}{3.16\times {10}^7}\text{year}\\ =3.17\times {10}^{-8}\text{year}\end{array}$

Conclusion:

Thus, the number of years in 1 second is $3.17\times {10}^{-8}\text{years}$