   Chapter 1, Problem 43GQ

Chapter
Section
Textbook Problem

Hexane (C6H14, density = 0.766 g/cm3), perfluoro-hexane (C6F14, density = 1.669 g/cm3), and water are immiscible liquids; that is, they do not dissolve in one another. You place 10 mL of each in a graduated cylinder, along with pieces of high-density polyethylene (HDPE, density = 0.97 g/cm3), polyvinyl chloride(PVC, density = 1.36 g/cm3), and Teflon (density = 2.3 g/cm3). None of these common plastics dissolves in these liquids. Describe what you expect to see.

Interpretation Introduction

Interpretation:

The observation made from the given compounds has to be described.

Concept introduction:

Density:

Density can be defined as property that links mass of an object to its volume.  It derived quantity and its unit is gml-1 for liquids and gcm-3 for solid.  The density of material can be calculated with the help of formula,

Density=Mass(g)Volume(mlorcm3)

Explanation

The density of liquids are given as,

Hexane  0.766 g/cm3Perfluorohexane = 1.669 g/cm3Water = 1 g/cm3Increasing orderof density is,Hexane<water< perfluorohexane.

On the basis of given density values the graduated cylinder forms three layers where the hexane will float on the top, water in the middle and perfluorohexane at the bottom.

The density of polymers is given as,

HDPE  0

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