(a) Interpretation: The boiling point of water in o M (new temperature scale) needs to be calculated if the melting point of mercury is 0 o M or − 38.9 o C and boiling point of mercury is 100 o M or 356.9 o C. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o M ) – T lower ( in o M ) ) ( T higher ( in o M ) – T lower ( in o M ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
The boiling point of water in oM (new temperature scale) needs to be calculated if the melting point of mercury is 0 oM or − 38.9 oC and boiling point of mercury is 100 oM or 356.9 oC.
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oM)– Tlower(in oM))(Thigher( in oM)– Tlower(in oM)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
Interpretation Introduction
(b)
Interpretation:
The absolute zero temperature in o M needs to be determined if melting point of mercury is 0 o M or − 38.9 o C and boiling point of mercury is 100 o M and 356.9 o C.
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oM)– Tlower(in oM))(Thigher( in oM)– Tlower(in oM)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
- When 2 kg of water vapor cools to a temperature of 373 K, the value of q=-930 KJ. If the specific heat of water vapor is 1.86 J/g degrees celsius, what is the initial temperature of water vapor in degrees celsius?
Please answer with a step by step explanation on how to solve, thanks!
When 3 kg of water vapor cools to a temperature of 373 k, the value of q=-1950 kJ. If the specific hear of water vapor is 1.86 J/g. degrees Celsius, what is the initial temperature of the water vapor in degrees celsius?
Please answer with a clear explanation and steps!
A ball has a kinetic energy of 5.90 kJ. If the ball has a mass of 120.0 g, how fast is the ball traveling, in meters per second?
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell