COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 1, Problem 49QAP
To determine

(a)

The limit of sodium intake per day for adult in unit of kilogram.

Expert Solution
Check Mark

Answer to Problem 49QAP

The sodium intake limit for adult is 2.5×103kg.

Explanation of Solution

Given info:

An adult cannot take more than 2500 mg per day.

Introduction:

The International System of Units is the most widely used system of measurement. It has seven basic unit and twenty-two derived units.

Convert the unit of sodium limit intake from milligram to kilogram.

  2500 mg=2500 mg×1kg 106g=2.5×103kg

Conclusion:

The sodium intake limit for adult is 2.5×103kg.

To determine

(b)

The concentration of cholesterol in a cup of milk in unit of kgm3 and mg/mL.

Expert Solution
Check Mark

Answer to Problem 49QAP

The concentration of cholesterol in a cup of milk is 0.146 kgm3 and 0.146 mg/mL.

Explanation of Solution

Given info:

A 240mL of milk contains 35mg of cholesterol.

Introduction:

The International System of Units is the most widely used system of measurement. It has seven basic unit and twenty-two derived units.

Formula used:

Formula to find the concentration of liquid is,

  Concentration =AmountofsubstanceVolumeofcontainer Equation-1

Find the concentration of milk in unit of mg/mL,

  Concentration =35mg240mL=0.146mg/mL

Find the concentration of milk in unit of kgm3

First find the amount of milk in unit of kg.

Convert the unit from milligram to kilogram,

  35mg=35mg×1g1000mg×1kg1000g=35×106kg

Find the volume of the cup in unit of meter-cube.

  240mL=240mL×1L1000mL×1m31000L=2.40×104m3

Next using equation-1 find the concentration in unit of kilogram per meter-cube.

  Concentration = 35×10 -6kg2.40 ×10 -4m3=0.146kg/m3

Conclusion:

Thus,the concentration of cholesterol in a cup of milk is 0.146 kgm3 and 0.146 mg/mL.

To determine

(c)

The volume of the cell.

Expert Solution
Check Mark

Answer to Problem 49QAP

The volume of the cell is 5.236×1016m3.

Explanation of Solution

Given info:

Diameter of the human cell is 10μm.

Formula used:

The formula to find the volume of the cell is,

VCell=43π(d2)3

Equation-1

Here, d is the diameter of the cell.

Calculation:

Find the volume of the cell by substituting the value of diameter in equation-1.

  Vcell=43π( 10 5μm)3=523.6(μm)3

Next convert the unit form micrometer cube to meter cube.

  Vcell=523.6(μm)3× ( 10 6 m )31 ( μm )3=5.236×1016m3

Conclusion:

Thus, form equation-2the volume of the cell is 5.236×1016m3.

To determine

(d)

The active ingredient 100 tablets of low strength aspirin.

Expert Solution
Check Mark

Answer to Problem 49QAP

The 100 tablets of low strength aspirin contains 81×10-4kg active ingredient.

Explanation of Solution

Given info:

Each tablet of low strength aspirin contains 81mg of active ingredient.

Introduction:

The International System of Units is the most widely used system of measurement. It has seven basic unit and twenty-two derived units.

Finding the active ingredient of each tablet of low strength aspirin:

Convert the unit of active ingredient intake from milligram to kilogram.

  81 mg=81 mg×1kg 106g=81×104kg

So, the hundred tablets contain

  M=81×106kg×100=81×104kg

Conclusion:

The 100 tablets of low strength aspirin contains 81×10-4kg active ingredient.

To determine

(e)

The average flow rate of urine from kidney in unit of m3/s.

Expert Solution
Check Mark

Answer to Problem 49QAP

The average flow rate of urine from kidney is 2.08m3/s.

Explanation of Solution

Given info:

The average flow rate of urine from kidney is 1.2mL/min.

Introduction:

The International System of Units is the most widely used system of measurement. It has seven basic unit and twenty-two derived units.

Find the volume of unit from milliliter per minute to meter-cube per second.

  1.2mL=1.2mL×1L1000mL×1m31000L=1.2×106m3

Find the unit of time from minutes to second.

  1min=1min×60s1min=60s

Thus, the unit of flow rate in meter cube is,

  Q =1 .2×10 -6m360s=2.08m3/s

Conclusion:

The average flow rate of urine from kidney is 2.08m3/s.

To determine

(f)

Thedensity of blood protein in unit of m3/s.

Expert Solution
Check Mark

Answer to Problem 49QAP

The density of blood protein is 1.6×103kg/m3.

Explanation of Solution

Given info:

The density of blood protein is 1.4g/cm3.

Introduction:

The International System of Units is the most widely used system of measurement. It has seven basic unit and twenty-two derived units.

Find the density of blood protein in unit of kg/m3.

Convert the unit of mass form grams to kilograms

  1.4g=1.4g×1kg1000g=1.4×10-3kg

Find the unit of volume from centi-meter cube to meter cube.

  1cm3=1cm3×1m3 106 cm3=106m3

Thus, the density in unit of kg/m3 is,

  Density =1 .2×10 -3kg 10 -6m3=1.6×103kg/m3

Conclusion:

The density of blood protein is 1.6×103kg/m3.

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