BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1, Problem 59RE
To determine

To simplify 1x12x21 by using appropriate operations.

Expert Solution

Answer to Problem 59RE

The answer is 1x+1 .

Explanation of Solution

Given information:

  1x12x21

Formula used:

Properties of fractions:- ACBC=ABC

Difference of squares : A2B2=(AB)(A+B)

Calculations:

First Term 1x1

Second Term 2x21

Denominator = x21

  x212=(x1)(x+1) (i)

Now,

  =1(x1)2(x1)(x+1)

writing the fraction in LCD (least common denominator) form we have,

  =(x+1)(x+1)(x1)2(x1)(x+1)

  =x+12(x+1)(x1)=(x1)(x+1)(x1)

  =1x+1 ( by cancelling (x1) )

After simplifying we get 1(x+1) .

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