# To simplify 1 x − 1 − 2 x 2 − 1 by using appropriate operations.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1, Problem 59RE
To determine

## To simplify 1x−1−2x2−1 by using appropriate operations.

Expert Solution

### Explanation of Solution

Given information:

1x12x21

Formula used:

Properties of fractions:- ACBC=ABC

Difference of squares : A2B2=(AB)(A+B)

Calculations:

First Term 1x1

Second Term 2x21

Denominator = x21

x212=(x1)(x+1) (i)

Now,

=1(x1)2(x1)(x+1)

writing the fraction in LCD (least common denominator) form we have,

=(x+1)(x+1)(x1)2(x1)(x+1)

=x+12(x+1)(x1)=(x1)(x+1)(x1)

=1x+1 ( by cancelling (x1) )

After simplifying we get 1(x+1) .

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