Chapter 1, Problem 5RCYU

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

A particular paint has a density of 0.914 g/cm3. You need to cover a wall that is 7.6 m long and 2.74 m high with a paint layer 0.13 mm thick. What volume of paint (in liters) is required? What is the mass (in grams) of the paint layer?

Interpretation Introduction

Interpretation:

The volume and mass of paint has to be given.

Concept introduction:

Density:

Density can be defined as property that links mass of an object to its volume.  It derived quantity and its unit is gml-1 for liquids and gcm-3 for solid.  The density of material can be calculated with the help of formula,

Density=Mass(g)Volume(mlorcm3)

Explanation

Given:Â densityÂ =Â 0.914Â g/cm3;Â longÂ =Â 7.6Â mÂ ;Â hieghtÂ =Â 2.74Â mÂ ;Â thicknessÂ =Â 0.13Â mm.volumeÂ ofÂ paintÂ =Â (thicknessÂ ofÂ paintÂ layer)Â Ã—(areaÂ ofÂ wall)CalculateÂ theÂ areaÂ ofÂ wall:_AreaÂ  Â =Â  lÃ—bâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰ (7.6Â m)(2.74Â m) Â =â€‰ 20.824Â m2CalculateÂ theÂ volumeÂ ofÂ paint:_volumeÂ ofÂ paintÂ  = Â (thicknessÂ ofÂ paintÂ layer)Â Ã—(areaÂ ofÂ wall)â€‰Volumeâ€‰â€‰â€‰â€‰ =â€‰â€‰ â€‰0.13Â mmâ€‰Ã—â€‰â€‰20.824Â m2 = 0

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