CHEMISTRY-TEXT
CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Textbook Question
Chapter 10, Problem 10.1P

Hurricane Irma (2017) had a central pressure of 914 mbar, the lowest recorded for an Atlantic hurricane. Calculate the pressure in units of mm Hg.

Expert Solution & Answer
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Interpretation Introduction

Interpretation:

The pressure of 914 mbar is to be expressed in mm Hg.

Concept introduction:

Atmospheric pressure is defined as average pressure that is exerted at the sea level. This is equivalent to exactly equivalent to 760 mm Hg column.

The relation between Pa and atm is as follows:

1 atm=101325 Pa

The conversion factor to convert atm to mm Hg is as follows:

1 atm=760 mm Hg

The conversion factor to convert mbar to bar is as follows:

1 mbar=103 bar

Answer to Problem 10.1P

The pressure is 685.55 mm Hg.

Explanation of Solution

Given information:

Central pressure is given as 914 mbar.

The conversion factor to convert mbar to bar is as follows:

1 mbar=103 bar

Therefore 914 mbar is converted to atm as follows:

Pressure=(914 mbar)(103 bar1 mbar)=914×103 bar

The conversion factor to convert bar to atm is as follows:

1 bar=0.986923 atm

Therefore 914×103 bar is converted to atm as follows:

Pressure=(914×103 bar)(0.986923 atm1 bar)=902.04×103 atm

The conversion factor for conversion of atm to mm Hg is as follows:

1 atm=760 mm Hg

Therefore 902.04×103 atm is converted to mm Hg as follows:

Pressure=(902.04×103 atm)(760 mm Hg1 atm)=685.55 mm Hg

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Chapter 10 Solutions

CHEMISTRY-TEXT

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