Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 10, Problem 10.4.3P
To determine
Nominal flexural strength of the given welded shape.
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Determine the nominal flexural strength of the following welded shape: The flanges are 3 inches x 22 inches, the web is 1⁄2 inch x 70 inches, and the member is simply supported, uniformly loaded, and has continuous lateral support. A572 Grade 50 steel is used.
In the truss loaded and supported as shown, computethe following using the Method of sections.(a) JK = ____________(b) KD = ____________(c) DE = ____________
2a) Justify the selection of a standard steel rolled section for the following Column from a bending moment diagram you determine that M is 200.7 MNmm at the support and the stress at that point in the beam is 175N/mm^2. Take into consideration an additional margin of safety as 20%.
Chapter 10 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
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- Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from Part 1 of the Manual will become slender. To which shapes does this value apply? What conclusion can you draw from your answer?arrow_forwardCalculate x if point B contacted with the square support? (Erod CD=200GPa; AB is a rigid bar without deformation)arrow_forwardPlese help me answer this. Thank you. Select an economic single unequal-leg-angle section for the tension member BH and GC for the truss shown.arrow_forward
- Compute the nominal shear strength of an M1211.8 of A572 Grade 65 steel.arrow_forwardA 66-foot long plate girder must support a uniformly distributed load and concentrated loads at the one-third points. The uniform load consists of a 1.3-kipyft dead load and a 2.3 kip/ft live load. Each concentrated load consists of a 28-kip dead load and a 49-kip live load. There is lateral support at the ends and at the one-third points. Use A572 Grade 50 steel, a total depth of 80 inches, and LRFD. a. Select the girder cross section and the required spacing of intermediate stiffeners. b. Determine the size of intermediate and bearing stiffeners. c. Design all weldsarrow_forwardA W18 3 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the available compressive strength if A992 steel is used?arrow_forward
- A plate girder cross section consists of two flanges, 11⁄2 inchesx 15 inches, and a 5⁄16-inch 3 66-inch web. A572 Grade 50 steel is used. The span length is 55 feet, the service live load is 2.0 kips/ft, and the dead load is 0.225 kips/ft, including the weight of the girder. Bearing stiffeners are placed at the ends, and intermediate stiffeners are placed at 69-20 and 12,-9,, from each end. Does this girder have enough shear strength? a. Use LRFD. b. Use ASDarrow_forwardA W420x85 steel beam is fully restrained with a uniformly distributed live load of 25 kN/m. The beam has a span of 10m. Use A36 steel. Properties of W40 x 85 A = 10839 mm2 bf = 180 mm tf = 18 mm tw = 11 mm Ix = 310 x 106 mm4 d = 420 mm (Note: Since this is a built-up section, for checking of web slenderness, use h = d - 2tf) 1) Calculate the design shear strength of the section. Check if the section is adequate in shear. USE LRFD and U = 1.2D + 1.6L. 2) Is the maximum deflection at the midspan of the beam due to live load adequate? 3) Calculate the maximum uniform live load that can be carried by the beam.arrow_forward
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ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning