   # The molar mass of a non electrolyte is 58.0 g/mol. Determine the boiling point of a solution containing 35.0 g of this compound and 600.0 g of water. The barometric pressure during the experiment was such that the boiling point of pure water was 99.725°C. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 115CWP
Textbook Problem
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## The molar mass of a non electrolyte is 58.0 g/mol. Determine the boiling point of a solution containing 35.0 g of this compound and 600.0 g of water. The barometric pressure during the experiment was such that the boiling point of pure water was 99.725°C.

Interpretation Introduction

Interpretation: The boiling point of given solution was calculated.

Concept Introduction:

Colligative properties of a substance include the depression in the freezing point, elevation of boiling-point and osmotic pressure. These are dependant only on the number present and not based on the solute particles present in an ideal solution. These properties have a direct relationship to the solute particles, and therefore the colligative properties are useful for identifying the nature of solute particles and also calculating the molar masses of substances.

The change in boiling-point expressed by the given equation

ΔTb=Kbm

Here Kb is molal boiling-point elevation constant.

### Explanation of Solution

Record the given data from question

Weight of given solute =35g

Weight of water =600g

To find the molality of given solution.

m=molesolutekgsolvent=35gsolute600gH2O×1000gkg×1molsolute58gsolute=1.01molal

To find the boiling point of given solution.

ΔTb=Kbm=0

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