Concept explainers
Interpretation:
The precipitated mass of calcium fluoride is to be calculated. The reactant which will be in excess is to be stated. The mass of the reactant that will be in excess is to be stated.
Concept introduction:
Answer to Problem 11PE
The precipitated mass of calcium fluoride is
Explanation of Solution
The balanced equation for the reaction is given below.
In the reaction,
Therefore, mole to mole ratio is given below.
Two conversion factors from the mole-to-mole ratio are given below.
The conversion factor to obtain moles of
The molar mass of sodium is
The molar mass of fluorine is
Therefore, the molar mass of
The formula to calculate the number of moles of
The mass of
Substitute the mass and molar mass of
The molar mass of calcium is
The molar mass of oxygen is
The molar mass of nitrogen is
Therefore, the molar mass of
The formula to calculate the number of moles of
The mass of
Substitute the mass and molar mass of
The number of moles of
The number of moles of
Therefore, the number of moles of
The moles of
The formula to calculate the mass of
Substitute molar mass and the mass of
Therefore, the mass of
In the reaction,
Therefore mole to mole ratio is given below.
Therefore, two conversion factors from the mole-to-mole ratio are given below.
The conversion factor to obtain moles of
Therefore, the number of moles of
The molar mass of calcium is
The molar mass of fluorine is
Therefore, the molar mass of
The formula to calculate the mass of
The number of moles of
Substitute the moles and molar mass of
Therefore the mass of
After the reaction, the mass of
Therefore, the precipitated mass of calcium fluoride is
The precipitated mass of calcium fluoride is
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Chapter 10 Solutions
Introductory Chemistry: An Active Learning Approach
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