   Chapter 10, Problem 13P

Chapter
Section
Textbook Problem

A pair of eyeglass frames are made of epoxy plastic (coefficient of linear expansion = 1.30 × 10−4 (°C)−1). At room temperature (20.0°C), the frames have circular lens holes 2.20 cm in radius. To what temperature must the frames be heated if lenses 2.21 cm in radius are to be inserted into them?

To determine
The temperature.

Explanation

Given Info: Radius of circular lens changes from r0=2.20cm to r=2.21cm . The room temperature is TR=20.0οC . Co-efficient of expansion of epoxy plastic ( α ) is 1.30×104/οC

Formula to calculate the temperature is,

T=TR+(Δrαr0)       (I)

• Δr is the change in radius.

The change in radius is,

Δr=rr0

Substitute rr0 for Δr in Equation (I).

T=TR+(rr0αr0)

Substitute 1

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