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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 14SR
Textbook Problem
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What volume of a 0.580-M solution of CaCl2 contains 1.28 g solute?

Interpretation Introduction

Interpretation: Required volume of  CaCl2 should be calculated.

Concept Introduction: Concentration of a solution can be defined in terms of molarity as moles of solute (in grams) to the volume of solution (in litres). It can be given by,

Concentration(inM)=Molesofsolute(ing)Volumeofsolution(inL)

Explanation of Solution

Record the data from the question

Weight of CaCl2= 1.28g

Molarity of CaCl2 = 0.58M

Molecular weight of CaCl2is=110.98g/mole

The volume of CaCl2 and Molarity of CaCl2  are recorded as shown above.

Calculated the Volume of CaCl2

1.28g CaCl2×1moleCaCl2110

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Chapter 10 Solutions

Chemistry: An Atoms First Approach
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