   Chapter 10, Problem 17QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# Calculate for each of the following cases.l type='a'> i> i> Interpretation Introduction

(a)

Interpretation:

ΔE should be calculated when q = + 65 kJ and w = -22 kJ

Concept Introduction:

The change in internal energy is equal to sum of heat and work done.

The mathematical expression is given as:

ΔE =q+w

Where, q = heat and w = work done.

If heat is released from the system, q is negative and if heat is absorbed by the system, q is positive.

If work is done on the system, w is positive and if work is done by the system, w is negative.

Explanation

Given information:

Work is done by the system = -22 kJ

Heat absorbed by the system = + 65 kJ

The mathematical expression is given as:

ΔE =q+w

Put the values,

w = -22 kJ and q =

Interpretation Introduction

(b)

Interpretation:

ΔE should be calculated when q = + 200. kJ and w = -73 kJ

Concept Introduction:

The change in internal energy is equal to sum of heat and work done.

The mathematical expression is given as:

ΔE =q+w

Where, q = heat and w = work done.

If heat is released from the system, q is negative and if heat is absorbed by the system, q is positive.

If work is done on the system, w is positive and if work is done by the system, w is negative.

Interpretation Introduction

(c)

Interpretation:

ΔE should be calculated when q = -18 kJ and w = -40. kJ

Concept Introduction:

The change in internal energy is equal to sum of heat and work done.

The mathematical expression is given as:

ΔE =q+w

Where, q = heat and w = work done.

If heat is released from the system, q is negative and if heat is absorbed by the system, q is positive.

If work is done on the system, w is positive and if work is done by the system, w is negative.

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