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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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Calculate Chapter 10, Problem 17QAP, Calculate for each of the following cases. l type='a'> i> i> , example  1for each of the following cases.

l type='a'>

  • Chapter 10, Problem 17QAP, Calculate for each of the following cases. l type='a'> i> i> , example  2
  • i>Chapter 10, Problem 17QAP, Calculate for each of the following cases. l type='a'> i> i> , example  3

    i>Chapter 10, Problem 17QAP, Calculate for each of the following cases. l type='a'> i> i> , example  4

    Interpretation Introduction

    (a)

    Interpretation:

    ΔE should be calculated when q = + 65 kJ and w = -22 kJ

    Concept Introduction:

    The change in internal energy is equal to sum of heat and work done.

    The mathematical expression is given as:

    ΔE =q+w

    Where, q = heat and w = work done.

    If heat is released from the system, q is negative and if heat is absorbed by the system, q is positive.

    If work is done on the system, w is positive and if work is done by the system, w is negative.

    Explanation

    Given information:

    Work is done by the system = -22 kJ

    Heat absorbed by the system = + 65 kJ

    The mathematical expression is given as:

    ΔE =q+w

    Put the values,

    w = -22 kJ and q =

    Interpretation Introduction

    (b)

    Interpretation:

    ΔE should be calculated when q = + 200. kJ and w = -73 kJ

    Concept Introduction:

    The change in internal energy is equal to sum of heat and work done.

    The mathematical expression is given as:

    ΔE =q+w

    Where, q = heat and w = work done.

    If heat is released from the system, q is negative and if heat is absorbed by the system, q is positive.

    If work is done on the system, w is positive and if work is done by the system, w is negative.

    Interpretation Introduction

    (c)

    Interpretation:

    ΔE should be calculated when q = -18 kJ and w = -40. kJ

    Concept Introduction:

    The change in internal energy is equal to sum of heat and work done.

    The mathematical expression is given as:

    ΔE =q+w

    Where, q = heat and w = work done.

    If heat is released from the system, q is negative and if heat is absorbed by the system, q is positive.

    If work is done on the system, w is positive and if work is done by the system, w is negative.

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