General, Organic, and Biological Chemistry - 4th edition
General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Question
Chapter 10, Problem 20P
Interpretation Introduction

(a)

Interpretation:

Atomic number for each isotope of nitrogen A and B given below should be predicted.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  1

Concept Introduction:

The atomic number of an atom is equal to the number of protons in it. The atomic number is represented by Z.

Expert Solution
Check Mark

Answer to Problem 20P

The atomic number for isotope of nitrogen A and B is 7.

Explanation of Solution

In the molecular model of fluorine, blue balls represent protons, whereas orange balls represent neutrons. Since the number of protons from given molecular model A and B is 7, the atomic number becomes 7 for A and B in both cases, as the atomic number is equal to the number of protons in that atom.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  2

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  3

Interpretation Introduction

(b)

Interpretation:

The mass number for each isotope of nitrogen A and B given below should be predicted.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  4

Concept Introduction:

The mass number is equal to the number of protons and neutrons in an atom.

Expert Solution
Check Mark

Answer to Problem 20P

The mass number for isotope of nitrogen A and B is 14 and 13 respectively.

Explanation of Solution

From the molecular model of an isotope of nitrogen, the number of neutrons can be counted. Thus, the number of neutrons in A and B is 7 and 6 respectively.

As Massnumber=Numberofprotons+Numberofneutrons

For A and B, the mass number will be calculated as follows:

  MassnumberofA=Numberofprotons+ Numberofneutrons=7+ 7= 14

  MassnumberofB=Numberofprotons + Numberofneutrons= 7 + 6= 13

Interpretation Introduction

(c)

Interpretation:

The number of protons for each isotope of nitrogen A and B given below should be predicted.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  5

Concept Introduction:

The number of protons is equal to the atomic number of that atom.

Expert Solution
Check Mark

Answer to Problem 20P

The number of protons in isotope of nitrogen A and B is 7.

Explanation of Solution

As the number of protons is equal to the atomic number in an atom. The atomic number of an isotope of nitrogen of A and B is 7. Thus, the number of protons in A and B will be 7.

Interpretation Introduction

(d)

Interpretation:

The number of neutrons for each isotope of nitrogen A and B given below should be predicted.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  6

Concept Introduction:

The mass number is the sum of all the protons and neutrons present in an atom. Thus, the number of neutrons can be calculated simply by subtracting the number of protons from the mass number of that atom.

Expert Solution
Check Mark

Answer to Problem 20P

The number of neutrons in A and B is 7 and 6 respectively.

Explanation of Solution

For A the mass number and number of protons are 14 and 7 respectively. Thus, the number of neutrons in A will be calculated as follows:

  MassnumberofA=Numberofprotons+ Numberofneutrons14=7+NumberofneutronsNumberofneutrons=14-7=  7

For B the mass number and number of protons are 13 and 7 respectively. Thus, the number of neutrons in B will be calculated as follows:

  MassnumberofB=Numberofprotons+Numberofneutrons13=7+NumberofneutronsNumberofneutrons=13-7= 6

Interpretation Introduction

(e)

Interpretation:

The isotope symbol for each isotope of nitrogen A and B given below should be predicted.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 10, Problem 20P , additional homework tip  7

Concept Introduction:

Isotopes are the compounds having the same atomic number but different atomic mass.

To write an isotope symbol atomic number (Z) is written on the lower left side and atomic mass(A) is written on the upper left side of an element.

Expert Solution
Check Mark

Answer to Problem 20P

The isotope symbol for A and B is 714N and 713N.

Explanation of Solution

For A, the mass number and atomic number are 14 and 7 respectively. Thus, the isotope symbol for A will be represented as follows:

  714N

For B, the mass number and atomic number are 13 and 7 respectively. Thus, the isotope symbol for B will be represented as follows:

  713N

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Chapter 10 Solutions

General, Organic, and Biological Chemistry - 4th edition

Ch. 10.2 - Prob. 10.3PPCh. 10.2 - Prob. 10.9PCh. 10.2 - Prob. 10.10PCh. 10.2 - Prob. 10.11PCh. 10.3 - Prob. 10.4PPCh. 10.3 - Prob. 10.12PCh. 10.3 - Prob. 10.13PCh. 10.3 - Prob. 10.14PCh. 10.4 - To treat a thyroid tumor, a patient must be given...Ch. 10.4 - A sample of iodine-131 (t1/2=8.0 days) has an...Ch. 10.4 - Prob. 10.15PCh. 10.5 - Prob. 10.16PCh. 10.5 - Prob. 10.17PCh. 10.5 - Prob. 10.18PCh. 10.6 - Prob. 10.7PPCh. 10.6 - Prob. 10.8PPCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Prob. 36PCh. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Prob. 43PCh. 10 - Prob. 44PCh. 10 - Prob. 45PCh. 10 - Prob. 46PCh. 10 - Prob. 47PCh. 10 - Prob. 48PCh. 10 - Prob. 49PCh. 10 - Prob. 50PCh. 10 - Prob. 51PCh. 10 - Prob. 52PCh. 10 - Prob. 53PCh. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - Prob. 56PCh. 10 - Prob. 57PCh. 10 - Prob. 58PCh. 10 - Prob. 59PCh. 10 - Prob. 60PCh. 10 - Prob. 61PCh. 10 - Prob. 62PCh. 10 - Prob. 63PCh. 10 - Prob. 64PCh. 10 - Prob. 65PCh. 10 - Prob. 66PCh. 10 - Prob. 67PCh. 10 - Prob. 68PCh. 10 - Prob. 69PCh. 10 - Prob. 70PCh. 10 - Prob. 71PCh. 10 - Prob. 72PCh. 10 - Prob. 73PCh. 10 - Prob. 74PCh. 10 - Prob. 75PCh. 10 - Prob. 76PCh. 10 - Prob. 77PCh. 10 - Prob. 78PCh. 10 - Prob. 79PCh. 10 - Prob. 80PCh. 10 - Prob. 81PCh. 10 - Prob. 82PCh. 10 - Prob. 83PCh. 10 - Prob. 84PCh. 10 - Prob. 85PCh. 10 - Prob. 86PCh. 10 - Prob. 87PCh. 10 - Prob. 88PCh. 10 - Prob. 89CPCh. 10 - Prob. 90CP
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