   Chapter 10, Problem 2P

Chapter
Section
Textbook Problem

The pressure in a constant-volume gas thermometer is 0.700 atm at 1.00 × 102°C and 0.512 atm at 0°C. (a) What is the temperature when the pressure is 0.040 0 atm? (b) What is the pressure at 450°C?

(a)

To determine
The temperature.

Explanation

Section 1:

Explanation:

To determine: The constants a and b.

The constant (a) is 1.88×103atm/οC

The constant (b) is 0.512 atm.

Given Info: The pressure ( P1 ) is 0.700 atm when temperature ( T1 ) is (1.00×102)οC . The pressure ( P2 ) is 0.512 atm when temperature ( T2 ) is 0οC .

Since, the volume is constant, the P-T graph is a straight line of the form,

P=aT+b                            (I)

• P is the pressure.
• T is the temperature.
• a and b are constants.

For the two sets of pressure and temperature,

P1=aT1+b                           (II)

P2=aT2+b                         (III)

From Equations (I) and (II),

a=P1P2T1T2                         (IV)

Substitute 0.700 atm for P1 , (1.00×102)οC for T1 , 0.512 atm for P2 and 0οC for T2 to get a.

a=(0.700atm)(0.512atm)[(1

(b)

To determine
The pressure.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 