   # An aqueous antifreeze solution is 40.0% ethylene glycol (C 2 H 6 O 2 ) by mass. The density of the solution is 1.05 g/cm 3 . Calculate the molality, molarity, and mole fraction of the ethylene glycol. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 30E
Textbook Problem
79 views

## An aqueous antifreeze solution is 40.0% ethylene glycol (C2H6O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity, and mole fraction of the ethylene glycol.

Interpretation Introduction

Interpretation:

The molality, molarity and mole fraction of ethylene glycol has to be calculated.

### Explanation of Solution

To calculate the molality of ethylene glycol:

Record the given info

Mass of Ethylene glycol = 40.0g

Density of solution = 1.05gcm-3

Molar mass of Ethylene glycol = 62.07g

Molality of Ethylene glycol = 40.0gC2H6O260gH2O×1000gkg×1molC2H6O262.07g

= 10.7molkg-1

Molality of Ethylene glycol = 10.7molkg-1

To calculate the molarity of the solution:

Record the given info

Mass of Ethylene glycol = 40.0g

Density of solution = 1.05gcm-3

Molar mass of Ethylene glycol = 62.07g

Molarity of solution = 40.0gC2H6O2100.0gsolution×1.05gcm3×1000cm3L×1molC2H6O262.07g

= 6

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