   Chapter 10, Problem 35P

Chapter
Section
Textbook Problem

Gas is confined in a tank at a pressure of 11.0 atm and a temperature of 25.0°C. If two-thirds of the gas is withdrawn and the temperature is raised to 75.0°C, what is the new pressure of the gas remaining in the tank?

To determine
The new pressure of the gas ( P2 ).

Explanation

Given Info: Initial pressure of the gas is P1=11.0atm . The temperature changes from T1=25οC to T2=75οC . When two third of the gas is withdrawn, the ratio of final ( n2 ) and initial ( n1 ) number of moles is 1/3.

From Ideal gas equation,

P1V=n1RT1       (I)

P2V=n2RT2       (II)

• V is the volume of the tank which doesn’t change.

Divide Equation (II) by (I) and re-arrange to get P2

P2=P1(n2n1)(T2T1)

Substitute 11

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