Chapter 10, Problem 41PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# You have two flasks of equal volume. Flask A contains H2 at 0 °C and 1 atm pressure. Flask B contains CO2 gas at 25 °C and 2 atm pressure. Compare these two gases with respect to each of the following: (a) average kinetic energy per molecule (b) root mean square speed (c) number of molecules (d) mass of gas

(a)

Interpretation Introduction

Interpretation:

The average kinetic energy of two gases given should be compared.

Concept Introduction:

• The temperature of the gas is proportional to the average kinetic energy of the gas.
• Average kinetic energy can be denoted by KE¯

KE¯=32RT32R-proportionalityconstantT-Temperature

• Equation which relates mass, average speed and temperature:

u2¯=3RTMu2¯-averagespeedM-Molecularmassu2¯-rootmeansquare(rms)

Explanation

The average kinetic energy of H2â€‰andâ€‰CO2 at different temperatures

â€‚Â H2â€‰â€‰â€‰â€‰-â€‰Temperatureâ€‰=â€‰0Â°Câ€‰=â€‰273â€‰Kâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰Pressureâ€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰1â€‰atmCO2Â -â€‰Temperatureâ€‰=â€‰25Â°Câ€‰=â€‰25+273â€‰=â€‰298â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰Pressureâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰2â€‰atm

Average kinetic energy can be calculated using the equation:

â€‚Â KEÂ¯â€‰=â€‰32â€‰RTâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰32â€‰Râ€‰â€‰-â€‰proportionalityâ€‰constantâ€‰â€‰â€‰â€‰Tâ€‰â€‰â€‰-â€‰Temperature

(b)

Interpretation Introduction

The average rms has be compared.

Concept Introduction:

• The temperature of the gas is proportional to the average kinetic energy of the gas.
• Average kinetic energy can be denoted by KE¯

KE¯=32RT32R-proportionalityconstantT-Temperature

• Equation which relates mass, average speed and temperature:

u2¯=3RTMu2¯-averagespeedM-Molecularmassu2¯-rootmeansquare(rms)

(c)

Interpretation Introduction

The average number of molecules of two gases given should be compared.

Concept Introduction:

• The temperature of the gas is proportional to the average kinetic energy of the gas.
• Average kinetic energy can be denoted by KE¯

KE¯=32RT32R-proportionalityconstantT-Temperature

• Equation which relates mass, average speed and temperature:

u2¯=3RTMu2¯-averagespeedM-Molecularmassu2¯-rootmeansquare(rms)

(d)

Interpretation Introduction

The average masses of two gases given should be compared.

Concept Introduction:

• The temperature of the gas is proportional to the average kinetic energy of the gas.
• Average kinetic energy can be denoted by KE¯

KE¯=32RT32R-proportionalityconstantT-Temperature

• Equation which relates mass, average speed and temperature:

u2¯=3RTMu2¯-averagespeedM-Molecularmassu2¯-rootmeansquare(rms)

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