Chapter 10, Problem 43PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# If the rms speed of an oxygen molecule is 4.28 × 104 cm/s at a given temperature, what is the rms speed of a CO2 molecule at the same temperature?

Interpretation Introduction

Interpretation: For the given rms speed value of oxygen molecule at particular temperature the rms speed for the CO2 molecule at same temperature should be determined.

Concept introduction:

The root mean square velocity μ is defined as the measure of velocity of particle in gas. It is the method to determine the single velocity value for particles.

Root mean square velocity can be determined,

μrms=(3RTM)1/2 (1)

(gas constant)R=8.314JKmolM=Molarmass

Molar mass: The molar mass of a substance is determined by dividing the given mass of substance by the amount of the substance.

Explanation

The expression used to calculate the rms speed is as follows,

â€‚Â â€‰Î¼rms=â€‰(3â€‰Râ€‰TM)1/2

Both the given gases differ only in the molar mass values since the temperature are same.

Now, equating the rms expression for both the given gases

â€‚Â â€‰â€Šâ€Šâ€Šâ€Šâ€Šâ€Šâ€Šâ€ŠÎ¼rmsofÂ O=(3â€‰Râ€‰TMO)1/2Î¼rmsofÂ CO2=â€‰(3â€‰Râ€‰TMCO2)1/2whereâ€Šâ€Šâ€Šâ€Šâ€Šâ€Šâ€Šâ€Šâ€Šâ€ŠMO=Â molarâ€ŠmassÂ ofÂ oxygenMCO2â€Šâ€Š=molarâ€ŠmassÂ ofâ€Šâ€Šcarbondioxide

While equating both the expressions the term 3â€‰Râ€‰T gets cancelled since it is same for both the molecules whereas the rms speed value and the molecular value remain since they are different for both the given gases

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started