   Chapter 10, Problem 50P ### University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185

#### Solutions ### University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185
Textbook Problem

# If a 1.50-cm-thick piece of lead can absorb 90.0% of the rays from a radioactive source, how many centimeters of lead are needed to absorb all but 0.100% of the rays?

To determine

The thickness of lead needs to absorb all except 0.100% of rays from a radioactive source.

Explanation

Giveninfo:

1.50 cm thick piece of lead absorbs 90% of gamma rays. The remaining part is 100%-90%=10%.

10100 = 0.100 part.

Formula used:

t=(1.5)xcm

Where, t = thickness

x =multiply

Calculations:

Consider there are x of the distance of 1.50cm to absorb all gamma rays except the remaining 0.100%.

Thus, the remaining part is,

0.100%=0.100100                = 0.00100 part.

Therefore, the expression is related as,

0.00100= (0.100)x

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