   Chapter 10, Problem 52AP

Chapter
Section
Textbook Problem

The active element of a certain laser is made of a glass rod 30.0 cm long and 1.50 cm in diameter. Assume the average coefficient of linear expansion of the glass is 9.00 × 10−6 (°C)−1. If the temperature of the rod increases by 65.0°C, what is the increase in (a) its length, (b) its diameter, and (c) its volume?

(a)

To determine
The increase in length.

Explanation

Given info: The length of the glass rod ( l0 ) is 30.0 cm. The diameter of the rod ( d0 ) is 1.50 cm. The co-efficient of linear expansion ( α ) is 9.00×106/οC . The increase in temperature ( ΔT ) is 65.0οC .

Formula to calculate the increase in length is,

Δl=αl0ΔT

Substitute 30.0 cm for l0 , 9.00×106/οC for α and 65

(b)

To determine
The increase in diameter.

(c)

To determine
The increase in volume.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 