   Chapter 10, Problem 56P ### University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185

#### Solutions ### University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185
Textbook Problem

# (a) Calculate the energy released in the neutron- Induced fission reaction n + 235 U → 92 K r + 142 B a + 2 n , given m(92Kr) = 91.926269 u and m(142Ba)= 141.916361 u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.

To determine

(a)

The energy released in the neutron induced fission reaction.

Explanation

Formula used:

The neutron induced fission reaction is given as,

n+235U92Kr+142Ba+2n

The mass difference is given as,

Δm=m(n)+m(235U)m(92Kr)m(142Ba)2m(n)

The energy released in the neutron induced fission reaction is given as,

E=(Δm)c2={m(n)+m( 235U)m( 92Kr)m( 142Ba)2m(n)

To determine

(b)

The conformation that the number of nucleons and the total charge is conserved during the reaction.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Find more solutions based on key concepts 