   # Reserpine is a natural product isolated from the roots of the shrub Rauwolfia serpenlina. It was first synthesized in 1956 by Nobel Prize winner R. B. Woodward. It is used as a tranquilizer and sedative. When 1.00 g reserpine is dissolved in 25.0 g camphor, the freezing-point depression is 2.63°C ( Kr for camphor is 40.°C · kg/mol). Calculate the molality of the solution and the molar mass of reserpine. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 71E
Textbook Problem
719 views

## Reserpine is a natural product isolated from the roots of the shrub Rauwolfia serpenlina. It was first synthesized in 1956 by Nobel Prize winner R. B. Woodward. It is used as a tranquilizer and sedative. When 1.00 g reserpine is dissolved in 25.0 g camphor, the freezing-point depression is 2.63°C (Kr for camphor is 40.°C · kg/mol). Calculate the molality of the solution and the molar mass of reserpine.

Interpretation Introduction

Interpretation:

Molality of the solution and molar mass of reserpine has to be calculated.

Concept Introduction:

Molality of the solution can be given by number of moles of solute present in the 1 kilogram of solvent.

Molality =number of moles ofsolute1kg of solvent

Molar mass: Molar mass of a compound can be given by mass of a substance to the amount of the substance. It can be given by expression

Molarmass=MassofasubstanceAmountofsubstance

### Explanation of Solution

To calculate molality of Reserpine:

Record the given data

Amount of Reserpine = 1.00g

Amount of Camphor at which Reserpine dissolved= 25g

The freezing point depression = 2.63°C

Molal freeing point depression constant (Kf) for Camphor = 40°C

26g = 0.0250kg

ΔTf= Kfm

m =ΔTfKf=2.63°C40°C kg/mol = 6.6×10-2mol Reserpinekg solvent

= 1.7×10-3mol Reserpine

To calculate molality of the solution:

0.0250 kg solvent × 6.6×10-2mol Reserpinekg solvent

=1.7×10-3mole

To calculate molar mass of Reserpine:

Record the given data

Amount of Reserpine = 1.00g

Amount of Camphor at which Reserpine dissolved= 25g

The freezing point depression = 2.63°C

Molal freeing point depression constant (Kf) for Camphor = 40°C

Molality of the solution = 1.7×10-3mole

Molar mass of Reserpine = 1

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