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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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A system releases 213 kJ of heat and has a calculated Chapter 10, Problem 78AP, A system releases 213 kJ of heat and has a calculated of 45 kJ. How much work was done on the of −45 kJ. How much work was done on the system?

Interpretation Introduction

Interpretation:

The work done on the system should be calculated.

Concept Introduction:

The internal energy, ΔE of a system is sum of potential energy and kinetic energy of all the particles. This can also be written in terms of work and heat as follows:

ΔE=q+w

Here, ΔE is change in internal energy, q is heat and w is work.

Explanation

Given Information:

The energy releases is 213 kJ and the value of change in internal energy is -45 kJ.

Calculation:

The internal energy is related to heat and work done as follows:

ΔE=q+w

Since, the heat is released thus, the value is -213 kJ

On rearranging and putting the values,

w=ΔE

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