   # Several small molecules (besides water) are important in biochemical systems: O 2 , CO, CO 2 , and NO. You have isolated one of these and to identify it you determine its molar mass. You release 0.37 g of the gas into a flask with a volume of 732 mL at 21 °C. The gas pressure in the flask is 209 mm Hg. What is the unknown gas? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 10, Problem 79GQ
Textbook Problem
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## Several small molecules (besides water) are important in biochemical systems: O2, CO, CO2, and NO. You have isolated one of these and to identify it you determine its molar mass. You release 0.37 g of the gas into a flask with a volume of 732 mL at 21 °C. The gas pressure in the flask is 209 mm Hg. What is the unknown gas?

Interpretation Introduction

Interpretation:

The unknown gas molar mass should be identified given the biochemical systems of O2, CO, CO2and NO molecules.

Concept Introduction:

Ideal gas Equation:

Any gas is described by using four terms namely pressure, volume, temperature and the amount of gas.  Thus combining three laws namely Boyle’s, Charles’s Law and Avogadro’s Hypothesis the following equation could be obtained.  It is referred as ideal gas equation.

nTPV = RnTPPV = nRTwhere,n = moles of gasP = pressureT = temperatureR = gas constant

Under some conditions gases don not behave like ideal gas that is they deviate from their ideal gas properties.  At lower temperature and at high pressures the gas tends to deviate and behave like real gases.

Boyle’s Law:

At given constant temperature conditions the mass of given ideal gas in inversely proportional to its volume.

### Explanation of Solution

Given the statement of values are

T = 21 oC = 273.15+21 = 294.15KP = 209 mmHgVolume=732mlMolar mass=0.37

PV=nRTn=PVRT209mmHg1atm209mmHg760mmHg=0.275732mL=1LitSo1lit=103ml0.732LMassMolarmass=0.275×0.7320.0821×294.15KMassMolarmass=0

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