   Chapter 10, Problem 80AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# Calculate the enthalpy change when 5.00 g of propane is burned with excess oxygen according to the reactionmg src=Images/HTML_99425-10-80AP_image001.jpg alt="" align="top"/>

Interpretation Introduction

Interpretation:

The enthalpy change when 5.00 g of propane is burned with excess oxygen should be calculated.

Concept Introduction:

Enthalpy of a reaction is a state function thus; change in enthalpy of a reaction does not depend on the path of the reaction.

The change in enthalpy is same if the same reaction takes place in one step or series of steps. This is known as Hess’s law. There are following characteristics of change in enthalpy which are important to calculate the change in enthalpy of a reaction using Hess’s law.

1. For a reversed reaction, the sign of enthalpy change of the reaction also reversed.
2. If any reactant or product is multiplied by any integer in the chemical reaction, enthalpy change of that reactant or product is also multiplied by the same integer.
Explanation

Given Information:

The mass of propane is 5.0 g

Calculation:

The balanced chemical equation for combustion of propane is as follows;

C3H8(g)+5O2(g)3CO2(g)+4H2O(l)

For the above reaction, enthalpy change is -2221 kJ.

In the above reaction, there is 1 mole of propane or C3H8 thus, -2221 kJ is amount of heat produced from combustion of 1 mole of propane.

Calculate the number of moles from given mass of propane

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