   # Use the following data for three aqueous solutions of CaCl 2 to calculate the apparent value of the van’t Hoff factor. Molality Freezing-Point Deperssion(°C) 0.0225 0.110 0.0910 0.440 0.278 1.330 ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 10, Problem 87E
Textbook Problem
476 views

## Use the following data for three aqueous solutions of CaCl2 to calculate the apparent value of the van’t Hoff factor. Molality Freezing-Point Deperssion(°C) 0.0225 0.110 0.0910 0.440 0.278 1.330

Interpretation Introduction

Interpretation: The van't Hoff factor of given CaCl2 solution should be calculated.

Concept introduction:

• Depression in freezing point:

The freezing point the solution is decreases when the solute is dissolved in the solvent is called Elevation of boiling point. it is one of the colligative Properties thus

ΔT=iKfmsolute......(2)ΔT is boiling-point elevationKfismolal freezing-point depression constantmis molality of the soluteiisthevan't Hoff factor

### Explanation of Solution

Record the given data,

Freezing-point depression of 0.0225mCaCl2=0.110

Freezing-point depression of 0.0910mCaCl2=0440

Freezing-point depression of 0.278mCaCl2=1.330

To calculate the Van't Hoff factor of 0.0225mCaCl2 solution.

i=ΔTfKfm=0.110°C1.86°C/molal×0.0225molal=2.63

To calculate the van't Hoff factor of 0.0910mCaCl2 solution.

i=ΔTfKfm=0.4401.86°C/molal×0.0910molal=2

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