   Chapter 10, Problem 94E

Chapter
Section
Textbook Problem

The temperature inside a pressure cooker is 115°C. Calculate the vapor pressure of water inside the pressure cooker. What would be the temperature inside the pressure cooker if the vapor pressure of water was 3.50 atm?

Interpretation Introduction

Interpretation: Inside the pressure cooker vapor pressure of water and temperature should be calculated.

Concept introduction:

Equilibrium vapor pressure:

• The pressure throw by vapor of the substance is equilibrium with liquid or solid state of same substance is called the equilibrium vapor pressure, thus,
•                     ln(Pvap1Pvap2)=ΔΗvapR(1T2-1T1)......(1)Pvap1andPvap2arevapor pressuresT1andT2aretemperaturesΔΗvapisenthalpy of vaporizationR is constant

• The liquids are boil when the vapor pressure of liquid is equal to atmospheric pressure.
Explanation

Explanation

Record the given data;

Temperature inside a pressure cooker = ll5°C

The entholpy ofvaporizationwater=40.7kJ/mol

The vapor pressure of water inside the pressure cooker =3.50 atm.

• The enthalpy of vaporization of water, temperature and pressure inside the pressure cooker are recorded as shown above.

To calculate vapor pressure of water inside the pressure cooker.

Constant R =8.3145J/K.mol

The vapor pressure of water at 100°C=1atm=760torr

ln(P21atm)=40.7×103J/mol8.3145J/K.mol(1373k-1388K)lnP2=0.51P2=e0.51P2=1.7atm

• The given and standard data are plugging in to the equation.
• The vapor pressure of water inside the pressure cooker is 1.7atm.

To calculate the temperature inside the pressure cooker at 3

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