   Chapter 10.1, Problem 26E Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Solutions

Chapter
Section Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

Use the method of Example 4 to find the equation of the line that describes all points equidistant from the points ( - 3 ,   4 ) and ( 3 ,   2 ) .

To determine

To find:

The equation of the line that describes all points equidistant from the points (-3, 4) and (3, 2).

Explanation

Given points are,

(-3, 4) and (3, 2).

Sketch the given coordinates in the graph and draw a line as shown in the figure.

The locus of the points equidistance from two fixed points is a line.

In the graph, MX is the line which is perpendicular bisector of AB-.

If X is on the locus, then AX=BX.

Coordinates of A=(-3, 4)

Coordinates of B=(3, 2)

Let the coordinates of X=(x,y)

AX=BX

(x+3)2+(y-4)2=(x-3)2+(y-2)2

(x+3)2+(y-4)2</

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