Mathematics All Around (6th Edition)
Mathematics All Around (6th Edition)
6th Edition
ISBN: 9780134434681
Author: Tom Pirnot
Publisher: PEARSON
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Chapter 10.3, Problem 1E

In Exercises 1-4, we give you a total population, state A’s population, and the total number of representatives that are to be apportioned. Find:

a. The standard divisor for the apportionment and the standard quota for A.

b. The number of representatives that would be given to the state using Jefferson’s method.

c. The number of representatives that would be given to the state using Adams’s method.

d. The number of representatives that would be given to the statue using Webster’s method.

Total population 512,000 ; A’s population 84,160 ; number of representatives being apportioned 16

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In the apportionment of the House of Representatives based on the 1790 Census, there are 15 states. At that time Maine was still considered part of Massachusetts. If Maine had been a separate state, it would have shared in the distribution of the seats in the House. In the 1790 census, Maine's population was 96,643. Subtract this number from Massachusetts' population and then answer the question .State_______________ Population Connecticut_______ 237,655 Delaware______________59,096 Georgia_________________82,548 Kentucky_______________73,677 Maryland_______________319,728 Massachusetts___________475,199 New Hampshire___________141,899 New Jersey_________________184,139 New York__________________340,241 North Carolina______________395,005 Pennsylvania________________433,611 Rhode Island__________________69,112 South Carolina______________249,073 Vermont_____________________85,341 Virginia______________________747,550 TOTAL_______________________3,893,874 What are the standard quotas…
Which one of the apportionment methods studied does not violate the quota rule? Group of answer choices Hamilton's Method Jefferson's Method Adam's Method Webster's Method
Using Webster's Method, if the modified quota is 50,100 and the population for State J is 1, 646,000, then the exact number of seats to be apportioned for State J is Group of answer choices 33 34 31 32

Chapter 10 Solutions

Mathematics All Around (6th Edition)

Ch. 10.1 - Sharpening your Skills Recall that on a 10-member...Ch. 10.1 - Sharpening your Skills Redo Exercise 11 for Aroco...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox...Ch. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 2ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Use the Jefferson method to assign the seats on...Ch. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Choosing representatives on a negotiations...Ch. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Use the Webster method to apportion the members of...Ch. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Use the Webster method to assign the number of...Ch. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Exercises 33-36Illustrate that the Jefferson and...Ch. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 4ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - In Exercises 15 and 16, use the method of sealed...Ch. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.CR - Prob. 1CRCh. 10.CR - Prob. 2CRCh. 10.CR - Prob. 3CRCh. 10.CR - Prob. 4CRCh. 10.CR - Prob. 5CRCh. 10.CR - Prob. 6CRCh. 10.CR - Prob. 7CRCh. 10.CR - Prob. 8CRCh. 10.CR - Prob. 9CRCh. 10.CR - Prob. 10CRCh. 10.CR - Prob. 11CRCh. 10.CR - Prob. 12CRCh. 10.CR - Prob. 13CRCh. 10.CR - Prob. 14CRCh. 10.CR - Prob. 15CRCh. 10.CR - Prob. 16CRCh. 10.CT - What is the Alabama paradox?Ch. 10.CT - Suppose state C has a population of 1,640,000 and...Ch. 10.CT - The Metropolitan Community College Arts Council...Ch. 10.CT - Prob. 4CTCh. 10.CT - Suppose that Arizona has a population of 5.23...Ch. 10.CT - Prob. 6CTCh. 10.CT - Prob. 7CTCh. 10.CT - Prob. 8CTCh. 10.CT - Prob. 9CTCh. 10.CT - Prob. 10CTCh. 10.CT - Prob. 11CTCh. 10.CT - Prob. 12CTCh. 10.CT - Prob. 13CTCh. 10.CT - Prob. 14CTCh. 10.CT - Three brothersLarry, Moe, and Curlyare dissolving...
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