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Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

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BuyFindarrow_forward

Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

Use the result in Exercise 26 to find the equation of the circle that has center (0, 0) and contains the point (3, 4).

To determine

To find:

The equation of the circle that has center (0, 0) and contains the point (3, 4).

Explanation

The circle that has center (0, 0) and contains the point (3, 4).

The above figure is circle and is drawn with center (0, 0) and contains the point (3, 4).

Here, x,y=(3, 4) is the point on the circle.

Hence the distance between the point (0, 0) and (3, 4) points is the radius of the circle.

Using distance formula for finding the length of the radius r as below,

r=(x-0)2+(y-0)2

Simplifying the above expression as below,

r=(3-0)2+(4-0)2

Take square root on both sides of the above expression,

r=(3)2+(4)2

r=9+16

r=25

r<

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