Find the vertex, focus and directrix of the parabola given by (x - 3)2 = 8(y + 1).Then graph the parabola.

Q: Find the vertex, focus, and directrix of the parabola. Sketch its graph, showing the focus and the…

A: y2-4y-2x-4=0 On simplification, we get ⇒y2-4y=2x+4⇒y2-4y+4=2x+4+4⇒y-22=2x+8⇒y-22=2x+4⇒y-22=2x--4 Now…

Q: Find an equation of the parabola with vertex (-5, -5) and directrix y = -11. D=0 ?

A:

Q: Find an equation of the parabola with vertex (-2,-4) and directrix y=-9.

A: given vertex (h,k)=(-2,-4) h=-2,k=-4 directrix y=k-p=-9                  p=k+9                p=-4+9…

Q: Find the standard form of the equation of the parabola with the given characteristics. y 10- Vertex…

A: Standard form of the parabola is:  Where (h,k)= vertex  p= distance between vertex and focus

Q: 21. What are the vertex, focus, and directrix of the parabola with equation y = x- 6x + 15?

A: Here we have to find the vertex, focus, and directrix of the parabola with the equation y=x2-6x+15

Q: Find the vertex, focus and directrix of the parabola given by y2 + 2y + 4x - 7 = 0.Then graph the…

A:

Q: Find the vertex, focus and directrix of the parabola given by (x - 2)2 = 4(y + 1)..Then graph the…

A:

Q: Find an equation of the parabola with vertex , −1−2 and focus , −5−2 .

A: Given information:The vertex of parabola is (1,2).The focus of parabola is (5,2)

Q: Find the standard equation of the parabola which satisfies the given condition. Vertex (-8, 3),…

A:

Q: Write the equation for a parabola with axis of symmetry: x=3, focus: (3, -1) and directrix: y=-7.

A:

Q: Find the focus, directrix, vertex and axis of symmetry for the parabola - 12(y + 2) = (x – 2)?. -

A:

Q: Find the vertex, focus, directrix, and focal width of the parabola. x2 = 28y

A:

Q: Classify the graph of the equation as circle, a parabola, an ellipse, ora Show your proof. 1.)9x² +…

A:

Q: Find the equation of the axis of symmetry of the following parabola using graphing technology. Y = y…

A: To find the axis of symmetry of the parabola.  y = x2 - 32x + 48.

Q: Find an equation of the parabola with vertex (-1,3) and directrix y=7 .

A:

Q: Find the focus and directrix of the parabola given by y2 = 12x. Then graph the parabola.

A: y2=12x Now comparing with y2=4ax, we get 4a=12⇒a=3 Therefore focus is, a, 0=3, 0 & directrix is,…

Q: A parabola has a vertex at the origin and a focus of (0, - 7). What is the equation of the parabola.

A:

Q: Determine the vertex, focus, directrix, and axis of symmetry of the parabola with the equation y =…

A:

Q: Write the equation of a parabola whose directrix is y = - 0.75 and has a focus at (– 8, 8.75).

A: Let's find.

Q: Locate the vertex, focus, directrix and axis of symmetry of the parabola y^2-5x+12y=-16.

A:

Q: Write the equation of a parabola whose directrix is y = 9 and has a focus at ( – 10, – 5). |

A: Given (-10, -5) is the focus and y=-9 is the directrix of parabola. Let x0, y0 be any point on the…

Q: Find an equation for the parabola that has its vertex at the origin and satisfies the given…

A: Given: The parabola has its vertex at the origin and  Directrix has y - intercept 8. We have to find…

Q: Find the focus and directrix of the parabola given by x2 = -8y. Then graph the parabola.

A:

Q: Find the equation of the parabola with vertex V (5,5) and directix the y-axis.

A: we have to find the equation of parabola

Q: Find the vertex,focus,and directrix of the parabola given by y2 + 2y + 12x - 23 = 0.Then graph the…

A: y2+2y+12x-23=0⇒y2+2y=-12x+23⇒y2+2y+1=-12x+23+1⇒y+12=-12x+24⇒y--12=-12x-2 Now comparing with…

Q: Use a graphing device to graph the parabola. y2 = -1/3x

A: Use the parametric form of parabola. The parametric form for the parabola of the form y2=-4ax is…

Q: Sketch the parabola and line on the same graph. y = 3x2 − 4  and  y = 2x + 4

A: point out zero of function and line and draw graph using these points

Q: Find the focus, the directrix, and the vertex of the parabola x^2 − x + 3y − 2 = 0

A:

Q: Find the standard form of the equation of the parabola with the given characteristics. y 10- Vertex…

A: Parabola Question

Q: What is the axis of symmetry of the parabola with equation (y - 1) = 4 (x – 1) ?

A:

Q: Find an equation of the parabola with focus (-9,-3) and directrix x=-1

A:

Q: Find the equation for the parabola with vertex (-3,0) and focus (0,0).

A:

Q: Find the vertex, focus, and directrix of the parabola (x-3)2=12(y+1) and sketch the graph of the…

A: The graph of given parabola is graphed in the step 2.

Q: The Focus and the Directrix of the parabola (x – 8)² = 8(y – 3) are -

A:

Q: Write an equation of the parabola with its vertex at (x, y) - (3, 9) and focus at (x, y) (3,-2).

A: The parabola has vertex at (h,k)= (3, 9) and focus at (h,k+a)= (3, -2) Hence axis of symmetry is x=3…

Q: Which is the equation of the parabola with focus (0, 8) and directrix y = – 8?

A: We will use the fundamental property of parabola.

Q: Find an equation of the parabola with focus (-6, -3) and directrix x= 4. ロ=ロ

A:

Q: Find the vertex, focus and directrix of the parabola given by y2 + 2y + 12x - 23 = 0..Then graph the…

A: Given equation, y2+2y+12x-23=0we have to find the vertex, focus and directrix of the given equation…

Q: Find the vertex, focus, and directrix of the parabola, and sketch its graph. x - 2x + 8y + 9-0…

A:

Q: Find the vertex, focus, foci and directrix of the parabola (x-6)^2+8(y+7)=0 and sketch its graph

A:

Q: Determine the equation of the parabola, focus (-3/2,3) and directrix at x=-37/2.

A:

Q: Find the vertex, focus, and directrix of the parabola y2 + 6y + 8x + 25 = 0, and sketch its graph.

A: Parabola:         y2+6y+8x+25=0=>y2+2.3y+9+8x+16=0=>(y+3)2=-8x-16=>-(y+3)28=x+2

Q: Find the standard form of the equation of the parabola with the given characteristics. y 1아 5 Vertex…

A:

Q: Find the focus and directrix of the parabola given by x²=-8y.then graph the parabola.

A:

Q: Determine the equation for the parabola from its graph. y Focus Vertex Axis of (-1, 1) (3, 1)…

A: Given query is to find the equation of the parabola.

Q: Find the vertex, focus, and directrix of the parabola (x − 6)2 − 2( y + 7) = 0, and sketch its…

A: Given: The equation of the parabola is, x-62-2y+7=0 The above equation can be converted into vertex…

Q: (x – 4) = –12 (y + 3) - Find the vertex, focus, and directrix of the parabola.

A: The given equation is: x-42=-12y+3                                     (1)

Q: Find the directrix of the parabola.  y^2= -10x

A:

Q: Find the standard form of the equation of the parabola with the given characteristics. y 10) Vertex…

A: Given vertex is (-3,0) and focus is (-1,0) find the standard equation of parabola

Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.